Given:
The radius of the cone = 14 ft
The slant height of the cone = 27 ft
To find the lateral surface area and the total surface area of the given cone.
Formula
The lateral surface area of the cone is
and
The total surface area of the cone is
![TSA = \pi r^{2} + \pi r l](https://tex.z-dn.net/?f=TSA%20%3D%20%5Cpi%20r%5E%7B2%7D%20%2B%20%5Cpi%20r%20l)
where,
r be the radius and
l be the slant height of the cone.
Now
Taking r = 14 and l = 27 we get
sq ft
or,
sq ft
Again,
sq ft
or,
sq ft
Hence,
The lateral surface area of the cone is 1187.5 sq ft and the total surface area of the cone is 1803.3 sq ft. Option C.
Answer:
D
Step-by-step explanation:
All real number less than 5
AC = 8.9
BC = 6.5
(90% angle)
8.9 x 6.5 = <span>57.85
57.85/2 = 28.925
Area of ^ABC = 28.925 cm squared
DE = 55.1
55.1/ 11.02 = 5
DEF is 5 times as big as ABC
DF = 44.5
FE = 32.5
44.5 x 32.5 = 1446.25
1446.25/2 = 723.125
I am not positive but I believe DEF = 723.125 cm squared
Good Luck on the Test!! :D
</span>
Answer:
-23
Step-by-step explanation:
Let first negative integer = x
The second = x +5
Their product = 126, hence,
x * (x +5) = 126
x^2 + 5x = 126
x^2 + 5x - 126 = 0
Two numbers whose product gives - 126 and sun gives 5
x(x + 14) - 9(x+14) =0
(x - 9) = 0 or (x + 14) = 0
x = 9 or x = - 14
Since x is said to be a negative integer,, the our x = - 14
First integer = - 14
Second integer = (x + 5) = (-14 + 5) = - 9
Sum of both integers :
-14 + - 9 = - 23