Showing powers of tens using exponents

For a confidence level of 85%, find the critical value for a normally distributed variable. The sample mean is normally distribu

const2013 [10]

Answer:

The value is $Z_{\alpha } = 1.439$

Step-by-step explanation:

From the question we are told that

The confidence level is C = 85%

Generally the level of significance is mathematically represented as

$\alpha = (100 - 85 )\%$

$\alpha = 0.15$

Now from the normal distribution table the critical value of $\alpha$ is

$Z_{\alpha } = 1.439$

7 0

3 years ago

$745 is deposited into an account that earns 4% simple interest for 8 years.

lara [203]

Step-by-step explanation:

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6 0

2 years ago

Read 2 more answers

about 1300 organ specimens are preserved in fluid. Typically contains 7/10 alcohol and 3/10 water. if one jar contains 19 pins o

DerKrebs [107]

5.7 pints would be water

3/10 of 19 pints are water

19*(3/10) = 5.7

4 0

3 years ago

What is the length of the cylinder's height? Please help

raketka [301]

Answer:

Height = 9 cm which means Option C is the answer

Step-by-step explanation:

In the question we are given ,

Volume of cylinder = 225π cm³

Radius of cylinder = 5 cm

And , we have to find the height of cylinder .

We know that ,

$\longrightarrow \pink{ \boxed{Volume \: of \: Cylinder = \pi r {}^{2}h }} \longleftarrow$

Our solution starts from here :

$\longmapsto \: \pi \: r {}^{2} h = 225\pi$

Step 1 : Cancelling π with π :

$\longmapsto \: \cancel{\pi} \: r {}^{2} h = 225 \cancel{\pi}$

Step 2 : Substituting value of radius which is 5 cm in the formula :

$\longmapsto \: (5) {}^{2} \times h = 225$

$\longmapsto \: 25h = 225$

Step 3 : Transposing 25 to right hand side :

$\longmapsto \: h = \frac{225}{25}$

Step 4 : Cancelling 225 by 25 :

$\longmapsto \: \red{\boxed{h = 9 \: cm}}$

Henceforth , height of cylinder is 9 cm

<h2 /><h2>#Keep Learning</h2>

8 0

1 year ago

Give the intervals where f(x) is concave up. (enter your answer using interval notation. if an answer does not exist, enter dn

Kipish [7]

Concave up is U-shaped.
There will be a inflection/critical point f'(x) =0 then a negative slope f'(x) = neg then another inflection/critical point f'(x) =0 at the bottom of the U-shape then a positive slope to last inflection/critical point. The interval for the Concave Up shape is the first and last inflection points.

6 0

3 years ago