The two numbers are 12 and 15
<em><u>Solution:</u></em>
Let the smaller number be "x"
Let the larger number be "y"
Given that,
<em><u>The sum of two numbers is 27</u></em>
Therefore, we frame a equation as:
Smaller number + Larger number = 27
x + y = 27 ------ eqn 1
<em><u>The larger number is 3 more than the smaller number</u></em>
Larger number = 3 + smaller number
y = 3 + x ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
x + 3 + x = 27
2x + 3 = 27
2x = 27 - 3
2x = 24
<h3>x = 12</h3>
<em><u>Substitute x = 12 in eqn 2</u></em>
y = 3 + 12
<h3>y = 15</h3>
Thus the two numbers are 12 and 15
The answer is 12.56 because when you divide 43.96 by 3 1/2 that is what you get.
Answer is option B.
Explanation:
5 to the power -2 can be written as
which will be
which will be
Answer:
4z+11
Step-by-step explanation:
11z-7z=4z
17-6=11
Answer:
a= -2
b= 1
c= 5
b^2-4ac= 41
The quadratic function will have 2 real number zeros
Step-by-step explanation:
Edguinity
