The drama club receives $7 for each ticket that they sell.
Step-by-step explanation:
Given,
Amount received by school = x dollars
Amount received by school for 96 tickets = 96x
Amount received by drama club = remaining amount after school
Total amount of 96 tickets = 96x+672
Here,
96x is the share of school
672 is the share of drama club for 96 tickets.
Therefore;
96 tickets = dollars
1 ticket = 
1 ticket = 7 dollars
The drama club receives $7 for each ticket that they sell.
Keywords: division, addition
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Answer:
if union, U means plus,+
if intersect means minus, -
Answer:
Explanation with the help of discrete variables and continuous variables.
Step-by-step explanation:
We have to tell that which of the following can be an exact number.
This can be done with the approach of discrete and continuous variables.
Discrete variables are the variables that are countable and cannot be expressed in decimal form. They are point estimated.
Continuous variable are the variable that are estimated with the help of an interval. Their values can be expressed with the help of a decimal expansion. They are not countable.
a) Mass of a paper clip, Surface are of dime, Inches in a mile, Ounces in pound, microseconds in a week
Since all mass, area, weight(ounces), time, length(inches) are continuous variable, they can be estimated with the help of an interval. Thus, they can have exact number but not always.
b) Number of pages in a worksheet
Since this is a discrete quantity and it is countable. Thus, it will always have a point estimation and are exact numbers always.
Answer:
x=−18
Step-by-step explanation:
Let's solve your equation step-by-step.
−8x=144
Step 1: Divide both sides by -8.
−8x−8=144−8
x=−18
We first obtain the equation of the lines bounding R.
For the line with points (0, 0) and (8, 1), the equation is given by:
For the line with points (0, 0) and (1, 8), the equation is given by:
For the line with points (8, 1) and (1, 8), the equation is given by:
The Jacobian determinant is given by
The integrand x - 3y is transformed as 8u + v - 3(u + 8v) = 8u + v - 3u - 24v = 5u - 23v
Therefore, the integration is given by:
![63 \int\limits^1_0 \int\limits^{1}_0 {(5u-23v)} \, dudv =63 \int\limits^1_0\left[\frac{5}{2}u^2-23uv\right]^{1}_0 \\ \\ =63\int\limits^1_0(\frac{5}{2}-23v)dv=63\left[\frac{5}{2}v-\frac{23}{2}v^2\right]^1_0=63\left(\frac{5}{2}-\frac{23}{2}\right) \\ \\ =63(-9)=|-576|=576](https://tex.z-dn.net/?f=63%20%5Cint%5Climits%5E1_0%20%5Cint%5Climits%5E%7B1%7D_0%20%7B%285u-23v%29%7D%20%5C%2C%20dudv%20%3D63%20%5Cint%5Climits%5E1_0%5Cleft%5B%5Cfrac%7B5%7D%7B2%7Du%5E2-23uv%5Cright%5D%5E%7B1%7D_0%20%5C%5C%20%20%5C%5C%20%3D63%5Cint%5Climits%5E1_0%28%5Cfrac%7B5%7D%7B2%7D-23v%29dv%3D63%5Cleft%5B%5Cfrac%7B5%7D%7B2%7Dv-%5Cfrac%7B23%7D%7B2%7Dv%5E2%5Cright%5D%5E1_0%3D63%5Cleft%28%5Cfrac%7B5%7D%7B2%7D-%5Cfrac%7B23%7D%7B2%7D%5Cright%29%20%5C%5C%20%20%5C%5C%20%3D63%28-9%29%3D%7C-576%7C%3D576)
