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Pavel [41]
3 years ago
8

Let f ( x ) = 10 x + 14 f − 1 ( x ) =

Mathematics
1 answer:
Agata [3.3K]3 years ago
6 0

Answer:

  f^-1(x) = (x -14)/10

Step-by-step explanation:

You can find the inverse function by solving for y:

  x = f(y)

Here, that is ...

  x = 10y +14 . . . . . use the definition of f(y)

  x -14 = 10y . . . . . . subtract 14

  (x -14)/10 = y . . . . divide by the coefficient of y

So, your inverse function is ...

  f^-1(x) = (x -14)/10

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Solve the system by the elimination method.
REY [17]

Answer: C is correct, 4x=8

Step-by-step explanation:

You will add the two equations...

4x-8=0

Now you need to move the -8 over, which reverses its sign to positive.

4x=8

8 0
3 years ago
1.Find the area of a trapezium with parallel sides of
Nana76 [90]

Answer:

The area of the trapezium is 74.8\ cm^2

Step-by-step explanation:

Area of a trapezium:

\displaystyle A=\frac{b1+b2}{2}h

This formula is valid if b1 and b2 are parallel and h is perpendicular to both.

Since the trapezium given in the problem satisfies those conditions, we use the formula with:

b1=15 cm

b2=7 cm

h=6.8 cm

\displaystyle A=\frac{15+7}{2}\cdot 6.8

A=74.8\ cm^2

The area of the trapezium is 74.8\ cm^2

6 0
3 years ago
3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

6 0
2 years ago
42 is 250% of what number
anzhelika [568]
42=2.50 × n.
2.50n/2.50. 42/2.50


16.8 is your answer
8 0
3 years ago
If 4.2km is 42cm on a map, what was the scale of the map?
Inessa05 [86]

Answer: I need da points

Step-by-step explanation: I’m just like that sry

8 0
3 years ago
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