Answer:
A precipitate will be produced
Explanation:
The Ksp of AgBr is:
AgBr(s) → Ag⁺ + Br⁻
5.0x10⁻¹³ = [Ag⁺] Br⁻]
<em>Where [] are the concentrations in equilibrium of each ion.</em>
<em />
And if Q is:
Q = [Ag⁺] Br⁻]
<em>Where the concentrations are actual concentrations of each ion</em>
<em />
We can say:
IF Q >= Ksp, a precipitate will be produced
IF Q < Ksp, no precipitate will be produced.
the molar concentrations are:
[AgNO₃] = [Ag⁺] = 0.002M * (50mL / 100mL) = 0.001M
<em>Because 50mL is the volume of the AgNO₃ solution and 100mL the volume of the mixture of both solutions.</em>
[NaBr] = [Br⁻] = 0.002M * (50mL / 100mL) = 0.001M
Q = [0.001M] * [0.001M]
Q = 1x10⁻⁶
As Q > Ksp,
<h3>A precipitate will be produced</h3>
Answer:
As the temperature of the water increases, the time needed for the dye to spread decreases. This is because the kinetic energy between the liquid particles increases, therefore helping the dye to dissolve and spread throughout the water.
Explanation:
It's B Covalent.Now I'll add more words since the thing says I need to write at least 20 characters.
Arrhenius model considers a base a compound that produces OH(-)
H2SO4 produces H(+) and is an acid
C6H12O6 is an organic product, sugar, that does not produce OH(-)
HOClO2 = HClO3, which produces H(+) and is an acid
NH3 is believed to ionize in water and produce NH4(+) and OH(-).
As per this the answer is NH3.
Nevertheless, NH3 is not a good example of bases as per Arrhenius model, because it is not so evident that NH3 produces OH(-).
