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Vlada [557]
3 years ago
14

Which phrase describes a polymer? A. a branching structure containing 10 carbon atoms and 22 hydrogen atoms B. a crystal contain

ing many sodium ions and many fluoride ions C. a long chain of carbon atoms with hydrogen atoms attached to them D. a molecule containing six carbon atoms arranged in a ring structure E. a single atom of calcium bonded to two atoms of chlorine
Chemistry
2 answers:
erica [24]3 years ago
5 0

Answer:

C. A long chain of carbon atoms with hydrogen atoms attached to them

Explanation:

For example, the main component of flour is starch and starch is a polymer.

Now, Starch is a polymeric carbohydrate that consists of a large number of glucose units which are bonded by chemical bonds known as glycosidic bond. It's also known that Starch is a white, tasteless and odorless powder that is not soluble in alcohol or even cold water.

Thus, we can say that polymer is a long chain of carbon atoms with hydrogen atoms attached to them.

Option C is correct.

Verdich [7]3 years ago
3 0

Answer:

C. A long chain of carbon atoms with hydrogen atoms attached to them

Explanation:

For example, the main component of flour is starch and starch is a polymer.

Now, Starch is a polymeric carbohydrate that consists of a large number of glucose units which are bonded by chemical bonds known as glycosidic bond. It's also known that Starch is a white, tasteless and odorless powder that is not soluble in alcohol or even cold water.

Thus, we can say that polymer is a long chain of carbon atoms with hydrogen atoms attached to them.

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14. In the lab, an experimenter mixes 75.0 g of water (initially at 30oC) with 83.8 g of a solid metal (initially at 600oC). At
avanturin [10]

Answer:

Tungsten is used for this experiment

Explanation:

This is a Thermal - equilibrium situation. we can use the equation.

Loss of Heat of the Metal = Gain of Heat by the Water

                      -Q_{m}=+Q_{w}\\

                    Q = mΔTC_{p}

Q = heat

m = mass

ΔT = T₂ - T₁

T₂ = final temperature

T₁ = Initial temperature

Cp = Specific heat capacity

<u>Metal</u>

m = 83.8 g

T₂ = 50⁰C

T₁ = 600⁰C

Cp = x

<u>Water</u>

m = 75 g

T₂ = 50⁰C

T₁ = 30⁰C

Cp = 4.184 j.g⁻¹.⁰c⁻¹

               -Q_{m}=+Q_{w}\\

⇒ - 83.8 x x x (50 - 600) = 75 x 4.184 x (50 - 30)

⇒ x = \frac{6276}{46090} = 0.13 j.g⁻¹.⁰c⁻¹

We know specific heat capacity of Tungsten = 0.134 j.g⁻¹.⁰c⁻¹

So metal Tungsten used in this experiment

8 0
3 years ago
A solution contains 90 milliequivalents of HC1 in 450ml. What is its normality?
Rashid [163]

Answer:

Normality N = 0.2 N

Explanation:

Normality is the number of gram of equivalent of solute divided of volume of solution, where the number of gram of equivalent of solute is weight of the solute divided by the equivalent weight.

Normality is represented by N.

Mathematically, we have :

\mathbf{Normality \ N = \dfrac{Number \ of \ gram \of \ equivalent\  of\  solute }{volume \ of \ solution}}

Given that:

number of gram of equivalent of solute = 90 milliequivalents 90 × 10⁻³ equivalent

volume of solution (HCl) = 450 mL 450 × 10⁻³ L

\mathbf{Normality \ N = \dfrac{90 \times 10^{-3}}{450 \times 10^{-3}}}

Normality N = 0.2 N

7 0
3 years ago
What are 4 similarities of Metals, Nonmetals, and Metalloids?
igor_vitrenko [27]
The answer is           


e o i and a



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7 0
3 years ago
Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an
garri49 [273]

Explanation:

The given data is as follows.

      T = 120^{o}C = (120 + 273.15)K = 393.15 K,  

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So,            x_{1} = 0.5   and   x_{2} = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

               p^{sat}_{1} (393.15 K) = 9.2 bar

               p^{sat}_{1} (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

                 p_{1} = x_{1} \times p^{sat}_{1}

                            = 0.5 \times 9.2 bar

                             = 4.6 bar

and,           p_{2} = x_{2} \times p^{sat}_{2}

                         = 0.5 \times 10.5 bar

                         = 5.25 bar

Therefore, the bubble pressure will be as follows.

                           P = p_{1} + p_{2}            

                              = 4.6 bar + 5.25 bar

                              = 9.85 bar

Now, we will calculate the vapor composition as follows.

                      y_{1} = \frac{p_{1}}{p}

                                = \frac{4.6}{9.85}

                                = 0.467

and,                y_{2} = \frac{p_{2}}{p}

                                = \frac{5.25}{9.85}

                                = 0.527  

Calculate the dew point as follows.

                     y_{1} = 0.5,      y_{2} = 0.5  

          \frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}

           \frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}

             \frac{1}{P} = 0.101966 bar^{-1}              

                             P = 9.807

Composition of the liquid phase is x_{i} and its formula is as follows.

                   x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{9.2}

                               = 0.5329

                    x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{10.5}

                               = 0.467

4 0
3 years ago
How many grams of sulfur will react with 6.75 g of silver? How many grams of silver sulfide (Ag2S) will be formed in this reacti
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Solve the following equation and check for extraneous solutions. Show all work. Thank you.

sqrt(sqrt(x - 3)) = sqrt(x - 15)
8 0
2 years ago
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