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erastova [34]
3 years ago
5

Given the following triangle find side AC. A. 11.89 B. 12.87 C. 13.98 D. 14.08

Mathematics
1 answer:
BigorU [14]3 years ago
7 0

Answer:

The answer to your question is AC = 14

Step-by-step explanation:

To solve this problem, we must use trigonometric functions.

And we must look for a trigonometric function that relates the opposite side and the hypotenuse.

This trigonometric function is the sine

   sin\alpha  = \frac{opposite side}{hypotenuse}

solve for Opposite side = AC

  AC = hypotenuse x sin α

- Substitution

  AC = 25 x sin 34

- Simplification

  AC = 25 x 0.56

- Result

  AC = 14

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Answer:

18

Step-by-step explanation:

95 divided by 5 equals 19

19-1=18

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A line has a rise of 3 and a run of 12. find the slope of the line. type a numerical answer in the space provided. if necessary,
muminat
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Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

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x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

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