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Vesnalui [34]
3 years ago
12

What is the molar mass off a substance?

Chemistry
2 answers:
Anon25 [30]3 years ago
4 0
The masses of the elements added together in the formula
aalyn [17]3 years ago
3 0
It is the mass of 1 mole in that substance
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When 18.0 mL of a 8.43×10-4 M cobalt(II) fluoride solution is combined with 22.0 mL of a 9.72×10-4 M sodium hydroxide solution d
Eva8 [605]

Answer:

Q = 1.08x10⁻¹⁰

Yes, precipitate is formed.

Explanation:

The reaction of CoF₂ with NaOH is:

CoF₂(aq) + 2 NaOH(aq) ⇄ Co(OH)₂(s) + 2 NaF(aq).

The solubility product of the precipitate produced, Co(OH)₂, is:

Co(OH)₂(s) ⇄ Co²⁺(aq) + 2OH⁻(aq)

And Ksp is:

Ksp = 3x10⁻¹⁶= [Co²⁺][OH⁻]²

Molar concentration of both ions is:

[Co²⁺] = 0.018Lₓ (8.43x10⁻⁴mol / L) / (0.018 + 0.022)L = <em>3.79x10⁻⁴M</em>

[OH⁻] = 0.022Lₓ (9.72x10⁻⁴mol / L) / (0.018 + 0.022)L = <em>5.35x10⁻⁴M</em>

Reaction quotient under these concentrations is:

Q = [3.79x10⁻⁴M] [5.35x10⁻⁴M]²

<em>Q = 1.08x10⁻¹⁰</em>

As Q > Ksp, <em>the equilibrium will shift to the left producing Co(OH)₂(s) </em>the precipitate

8 0
4 years ago
A non-mechanical, rigid, and fully insulated mixing tank is used to combine two inflows to produce wet steam. One inflow consist
Bogdan [553]

Explanation:

As it is given that stream A is super heated. From stream tables, we get that specific enthalpy, (h_{A}) is 3054.29 kJ/kg.

For stream B, it is saturated water at 25 degree celsius. It's h_{B} is 2546.54 kJ/kg.

Stream C, data will be as follows.

                P = 200 kPa,         \chi = 0.9

So, h_{c} = h_{f} + \chi \times h_{fg}  

        = 504.47 + 0.9 \times 2201.7

        = 2486 kJ/kg

Now, energy balance formula will be as follows.

            m_{A}h_{A} + m_{B}h_{B} = (m_{A} + m_{B})h_{c}

              3 \times 3054.29 + m_{B} \times 2546.54 = (3 + m_{B}) \times 2486

             m_{B} = 28.16 kg/s

Hence, inflow of saturated liquid is 28.16 kg/s. According to steam table, temperature of wet steam is 120.23^{o}C

Mass flow rate of out flow is 31.16 kg/s.

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