<span><span>KaAcid</span><span><span>1.0 * 109</span>Hydrobromic acidHBr</span><span><span>1.3 * 106</span>Hydrochloric acidHCl</span><span><span>1.0 * 103</span>Sulfuric acid<span>H2SO4</span></span><span><span>2.4 * 101</span>Nitric acid<span>HNO<span>3</span></span></span></span>
There are TWO atoms in one molecule of hydrogen.
<span>Separate this redox reaction into its component half-reactions.
Cl2 + 2Na ----> 2NaCl
reduction: Cl2 + 2 e- ----> 2Cl-1
oxidation: 2Na ----> 2Na+ & 2 e-
2) Write a balanced overall reaction from these unbalanced half-reactions:
oxidation: Sn ----> Sn^2+ & 2 e-
reduction: 2Ag^+ & 2e- ----> 2Ag
giving us
2Ag^+ & Sn ----> Sn^2+ & 2Ag </span>Steve O <span>· 5 years ago </span><span>
</span>
It would be C i’m pretty sure