Mixtures are made up of 2 or more pure substances. pure substance is just its self and a mixture is multiple substances.
<span>You can compare the strength of the hydrogen bonding by comparing the electronegativities of the other elements. All the four elements, Br, F, Cl and I belong to the same group in the periodic table: group 17 named halogens. Then the kind of bonding they form is similar: polar covalent. You must know the trend of the electronegativities in the periodic table. Electronegativity decrease when you down across a group. Then the electronegativity of F is the higher of the group (indeed, it is the highest of all the 118 elements) . The higher the electronegativity the stronger the attraction that the halogen attracts the electrons and the stronger the hydorgen bonding. Then, the conclusion is that HF has the strongest hydrogen bonding. </span>
Answer:
The two most useful properties of titanium include its resistance to corrosion and its high strength-to-weight ratio.
Chromium metal is highly valuable due to its high corrosion resistance and hardness.
Manganese is a metal with important industrial metal alloy uses, particularly in stainless steels.
Explanation:
Answer:
Yes, acetic acid could be used, but it would not be as effective as acetyl chloride or acetic anhydride. ... However, the acetic anhydride would still be reacting with an alcohol, so nothing changes in that respect. Also, the reaction would need to be done in basic solution.
Answer:
Explanation:
Hello,
In this case, by using the Henderson-Hasselbach equation one could compute the pH considering that the pKa of hydrofluoric acid, HF, is 3.14:
![pH=pKa+log(\frac{[base]}{[acid]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D%20%29)
Whereas the concentration of the base and acid are computed by considering the mixing process with a total volume of 300 mL (0.3 L):
![[HF]=\frac{0.005molHF}{0.3L}=0.017M](https://tex.z-dn.net/?f=%5BHF%5D%3D%5Cfrac%7B0.005molHF%7D%7B0.3L%7D%3D0.017M)
![[NaF]=\frac{0.02molHF}{0.3L}=0.067M](https://tex.z-dn.net/?f=%5BNaF%5D%3D%5Cfrac%7B0.02molHF%7D%7B0.3L%7D%3D0.067M)
Therefore, the pH turns out:
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