Question

A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what is the pressure after the temperature change?
Use mc006-1.jpg.

0.75 atm
0.89 atm
1.1 atm
1.3 atm

Answer 1

0.75 atm. is the answer

Answer 2

Answer  will be 0.75 atm .

According to gas law given by  Gay lussac-

"pressure of a gas is directly proportional to the temperature(kelvins) of the gas when volume is kept constant".

                                 $\frac{P_1}{T_1}=\frac{P_2}{T_2}$

given:

         $P_{1}=0.82 atm$

         $T_{1}=21^{\circ}C=21+273.15K=294.15K$

         $P_{2}=?$

         $T_{2}=-3.5^{\circ}C=-3.5+273.15K=269.65K$

Now putting the respective values is the equation (1)

                      $\frac{P_1}{T_1}=\frac{P_2}{T_2}$

                   $\frac{0.82}{294.15}=\frac{P_2}{269.65}$

                                      $P_{2} = 0.75 atm$