Answer:
I'm telling you once in my life, I committed mistake and I'M NOT POINT STEALER. put that in mind. You hurt me.
Let's solve for x.
2x+3y=5
Step 1: Add -3y to both sides.
2x+3y+−3y=5+−3y
2x=−3y+5
Step 2: Divide both sides by 2.
2x
2
=
−3y+5
2
x=
−3
2
y+
5
2
Answer:
x=
−3
2
y+
5
2
Step-by-step answer:
We are looking at the coefficient of the 22nd term of (x+y)^25.
Following the sequence, first term is x^0y^25, second term is x^1y^24, third term is x^2y^23...and so on, 22nd term is x^21y^4.
The twenty-second term of (x+y)^25 is given by the binomial theorem as
( 25!/(21!4!) ) x^21*y^4
=25*24*23*22/4! x^21y^4
= 12650 x^21 y^4
The coefficient required is therefore 12650, for a binomial with unit valued coefficients.
For other binomials, substitute the values for x and y and expand accordingly.
Question would have been more clearly stated if the actual binomial was given, as commented above.
Answer:
hmm
Step-by-step explanation:
4+3+1+1+1+1+1 =12
4x3x1x1x1x1x1=12
12/18
6/9
2/3
Simply in common factor you know and keep doing it
12/18
BCD:6
2/3