Look at deonomators
assuming that the deonomenators are 5x+15y and 2x+6y
find their LCM
factor
5x+15y=5(x+3y)
2x+6y=2(x+3y)
LCM=10(x+3y)=10x+30y
multiply 2/(5x+15y) by 2/2=4/(10x+30y)
multiply 1/(2x+6y) by 5/5=5/(10x+30y)
if we add them
9/(10x+30y)
Answer:
e = -1/2
Step-by-step explanation:
4/3 = -6e - 5/3
transfer -6e to the right
4/3 = -5/3 -6e
Find the LCM of 3,3and 1
and their LCM is 3. So, divide all through by 3
3(4/3) = 3(-5/3) - 6e × 3
4 = -5 -18e
combine
4 + 5 = -18e
9 = -18e
divide by -18
9/ -18 = -18e/ -18
-1/2 = e
e = -1/2
\left[x _{2}\right] = \left[ 6+\sqrt{33}\right][x2]=[6+√33]
Answer:thre
Step-by-step explanation:
A) - 14 is the correct answer
