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Alona [7]
3 years ago
7

Integrate 2x/sqrt(1-x^2) dx from 0 to ½.

Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0
A short-cut to accurately evaluate the given expression above is using a scientific calculator where one can include integrals and evaluate using limits. In this case, using a calculator, the answer is equal to 0.2679. One can verify this by integrating truly letting 1-x^2 as u and use its du to be substituted in the numerator
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Please help me with this problem :) <br> show ur work please
Marina CMI [18]

Answer:

\boxed{w = 14.9} \: or \: you \: can \: say \:  \underline{\boxed{w = 15} }

Step-by-step explanation:

applying \: the \: pythagorean \: rule :  \\  {(hyp)}^{2}  = {(adj)}^{2}   +  {(opp)}^{2}  :  \\  {w}^{2}  =  {11}^{2}  +  {10}^{2}  \\  {w}^{2}  = 221 \\ w =  \sqrt{221}  \\  \boxed{w = 14.866068747}

7 0
3 years ago
. The selling price of 15 articles is Rs 1,500 at a gain of 8%. Find C.P of each article<br>​
Andru [333]

<u>Rs. 92.59</u> is each article's CP

Step-by-step Explanation:-

As per conditions given,

1500 \div 15 \div (1 + 8%)

=  > 100 \div 1.08

=  > approx. \: 92.59

Hence, the CP of each article is <u>Rs. 92.59</u>

3 0
2 years ago
Hey I'm taking a math exam tomorrow please send words of encouragement please answer.
o-na [289]

Answer:

did you study????? well if u did then why u scareddd shortteee.

6 0
2 years ago
The coordinates of Point A are (6,3). Point B is a reflection of Point A across the y axis. In which Quadrant is point B located
Ksju [112]

point B is located in quadrant II (option B)

Explanation:

Point A: (6, 3) = (x, y)

reflection of point A across the y axis:

The x coordinate will be negative and the y coordinate will remain the same

reflection of point A across the y axis = (-6, 3)

Attaching the graph showing the point after reflection:

Since point B is the reflection of point A.

Hence, point B is located in quadrant II (option B)

8 0
1 year ago
What is the difference?
Ganezh [65]

Answer:

\frac{x^2+4x-1}{x(x+2)}

Step-by-step explanation:

Given

\frac{x+5}{x+2} - \frac{x+1}{x^2+2x} ← factor denominator

= \frac{x+5}{x+2} - \frac{x+1}{x(x+2)}

We require the fractions to have a common denominator.

Multiply numerator/denominator of first fraction by x

= \frac{x(x+5)}{x(x+2)} - \frac{x+1}{x(x+2)}

Subtract terms on numerator leaving the common denominator

= \frac{x^2+5x-x-1}{x(x+2)}

= \frac{x^2+4x-1}{x(x+2)}

7 0
3 years ago
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