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stira [4]
3 years ago
10

Can anyone do the top problem for me?

Mathematics
2 answers:
ANTONII [103]3 years ago
8 0
It’s c I just took the quiz yesterday
kolezko [41]3 years ago
7 0

Answer:

C

Step-by-step explanation:

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Given the diagram below find x, and the measure of
Sophie [7]

Answer:

8, 40 , 50

Step-by-step explanation:

the measure of A is 90°

so 5x + 7x - 6 = 90

now.. to find the x

5x + 7x - 6 = 90

5x + 7x = 90 + 6

12x = 96

x = 96/12

x = 8

so the measure of angle A1 is (5*8) = 40

the measure of angle A2 is (7*8-6) = 50

finaly the angle A is (50+40) = 90

8 0
4 years ago
PLZ HELP !
max2010maxim [7]

Answer:

13 cm

Step-by-step explanation:

The diagonal of a rectangle forms a right triangle; where the diagonal is a hypotenuse, and two sides of the rectangle are legs.

Using pythagorean's theorem (a^2 + b^2 = c^2), we can say:

5^2 + 12^2 = c^2\\25 + 144 = c^2\\169 = c^2\\13 = c

The hypotenuse is equal to 13cm.

3 0
4 years ago
Abby owns a comic book that originally sold for 12¢ in 1969. In 2014, the comic book had an appraised valued of $3,700. Given th
choli [55]

Solution

2014 - 1969 = 45

45 x 0.2633 = 11.8485 = 12

Final Answer:

C) 26.33%

6 0
3 years ago
How to solve x in a trapezoid
Cloud [144]
For Volume is V=(base1 + base2)h and then divide by two
4 0
3 years ago
Read 2 more answers
Suppose a set of test scores is appproximately bell-shaped, with a mean of 68 and a range of 54. (a) The minimum test score is a
liberstina [14]

Answer:

a.) Minimum test score = 41

    Maximum test score = 95

b.)An approximate value of the standard deviation is 9.

Step-by-step explanation:

The given set of test scores is approximately bell shaped.

The mean of the test scores, \mu = 68

The range of the data set = 54.

a.) i.) Minimum test score  = \mu - \frac{range}{2}  = 68 - \frac{54}{2}  = 68 - 27 = 41

   ii.) The maximum test score = \mu + \frac{range}{2}  = 68 + \frac{54}{2}  = 68 + 27 = 95

b.) From the 68-95-99.7 rule, also known as the Empirical rule, tell us that an approximation of the range is 3 standard deviations either way from the mean. So from this rule we can say that the minimum can also be found from \mu - 3\sigma and the maximum can also be approximated as \mu + 3\sigma.

From the above we can say that the range can be written as

   3\sigma - (-3\sigma) = range

∴   6\sigma  = range

∴    \sigma  = \frac{range }{6}  = \frac{54}{6}  = 9

Therefore an approximate value of the standard deviation is 9.

7 0
3 years ago
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