All categories

3 years ago

Please I really need help with this

Mathematics

1 answer:

Delvig [45]3 years ago

6 0

Answer:

Step-by-step explanation:

㏒ 3+㏒(x+2)=1

㏒3(x+2)=1

3(x+2)=10^1

3x+6=10

3x=10-6=4

x=4/3

so A

$log_{2}x+log_{2}(x+2)=3\\or~log_{2}[x(x+2)]=3\\x(x+2)=2^3\\x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x+4)(x-2)=0\\x=2,-4\\x=-4 ~is~an~extraneous~solution.\\B$

You might be interested in

Graph the set of real numbers on a number line. {x|x> -5} Mathematics

frutty [35]

The answer is just -5

4 0

3 years ago

A marketing consultant observed 50 consecutive shoppers at a supermarket. One variable of interest was how much each shopper spe

Diano4ka-milaya [45]

Answer:

a. $\\ \mu = USD\;51.34$ ; b. The 95% interval is USD [45.82, 56.86].

Step-by-step explanation:

The mean amount a customer spends at the grocery store

The mean is the sum of all of the data divided by the number of observations for this case, that is, n = 50.

The sum of all of the data is: 5.24+11.97+13.59+15.52+15.69+19.96+20.54+22.59+27.25+27.29+28.25+30.00+31.63+33.01+37.21+40.36+40.90+42.83+45.66+46.67+47.49+49.32+50.12+51.71+52.2 1+53.57+56.16+56.36+56.88+58.65+59.42+60.20+60.48+62.23+62.50+67.95+70.45+73.08+74.15+74.48+74.78+75.75+76.27+76.47+78.92+84.09+84.91+85.06+88.45+88.91 = 2567.17.

The mean $\\ \mu$ is

$\\ \mu = \frac{2567.17}{50}$

$\\ \mu = \frac{2567.17}{50} = 51.34$

Then, the mean amount a customer spends at the grocery store is USD 51.34.

The 95% confidence interval for the mean amount spent

For the 95% confidence interval for the mean, we have the value for the mean = 51.34, as we have just found, the value for the standard deviation is already given as USD 20.00. There are 50 observations, so n = 50.

Moreover, for a 95% confidence, the value for the corresponding z-score is z = 1.96 (this is the confidence coefficient). Then, the formula for finding the "limits" values for the confidence interval is as follows:

For the upper limit

$\\ \overline{X} + 1.96*\frac{\sigma}{\sqrt{n}}$

$\\ 51.34 + 1.96*\frac{20}{\sqrt{50}}$

$\\ 51.34 + 5.52$

$\\ 56.86$

For the lower limit

$\\ \overline{X} - 1.96*\frac{\sigma}{\sqrt{n}}$

$\\ 51.34 - 1.96*\frac{20}{\sqrt{50}}$

$\\ 51.34 - 5.52$

$\\ 45.82$

Thus

The 95% confidence is USD [45.82, 56.86].

Mathematically

$\\ P(45.82 \leq \mu \leq 56.86) = 0.95$

There is a probability of 0.95 that the values are between [45.82, 56.86], both inclusive.

We have to remember here that we are dealing with a sample. This sample has a standard deviation, called standard error of the sample, and is $\\ \frac{20}{\sqrt{50}} \approx 2.83$ .

So, the population mean is, with a 95% confidence, between the values [45.82, 56.86], both inclusive.

We can see the graph below that represents the former.

3 0

3 years ago

A right rectangular prism has a volume of

777dan777 [17]

Answer:

3x, 2x + 5, and x - 3

Step-by-step explanation:

Since the given figure is a 3-dimensional shape, we know that there must be three zeroes.

Our equation is:

6x³ - 3x² - 45x

First, we can factor out an x:

x (6x² - 3x - 45)

From here, we can see that by factoring out a 3:

3x (2x² - x - 15)

Now, after completing the square and factoring:

3x (2x + 5) (x - 3)

These are our three expressions.

4 0

3 years ago

Anybody good in geometry and know how to do this? Free Brainliest and points .

Scrat [10]

Answer:

im guessing the answer would be C but im not sure

before hand sorry if you get it wrong

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Jada has a stand in the marketplace where she sells ground cumin. Her weekly expenses are $300, and she sells her cumin at a fix

Scrat [10]

P = R - E
600 = 120x - 300
The value of x from the equation is 7.5. The answer therefore for the first question is $7.5. Then, the number of kilogram of cumin she needs to sell to cover the expenses is $300/$7.5 and that is equal to 40.
I tried my best hope this helps

7 0

4 years ago