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Ahat [919]
3 years ago
14

Please I really need help with this

Mathematics
1 answer:
Delvig [45]3 years ago
6 0

Answer:

Step-by-step explanation:

㏒ 3+㏒(x+2)=1

㏒3(x+2)=1

3(x+2)=10^1

3x+6=10

3x=10-6=4

x=4/3

so A

3.

log_{2}x+log_{2}(x+2)=3\\or~log_{2}[x(x+2)]=3\\x(x+2)=2^3\\x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x+4)(x-2)=0\\x=2,-4\\x=-4 ~is~an~extraneous~solution.\\B

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Draw the graphs of the equations x – y = 1 and 2x + y = 8. Shade the area bounded by these two lines and y-axis. Also, determine
NikAS [45]

Answer:

Using Geometry to answer the question would be the simplest:

Step-by-step explanation:

Remembering the formula for the area of a triangle which is A=\frac12bh. One can then tackle the question by doing the following:

Step 1 Find the y-intercepts

The y-intercepts are found by substituting in x=0.

Which gives you this when you plug it into both equations:

-y=1\\y=-1\\y=8

So the y-intercepts for the graphs are (0,-1)\\, and (0,8) respectively.

Now one has to use elimination to solve the problems by adding up the equations we get:

x-y=1\\2x+y=8\\3x=9\\x=3

Now to solve for the y component substitute:

2(3)+y=8\\y=2

Therefore, the graphs intersect at the following:

(3,2)

Now we have our triangle which is accompanied by the graph.

now to solve it we must figure out how long the base is:

b=8-(-1)\\b=9

The height must also be accounted for which is the following:

h=3

Now the formula can be used:

A=\frac12bh=\frac12(9)(3)=\frac{27}2\ \text{units}^2

7 0
2 years ago
Read 2 more answers
Miguel buys 100 feet of fence to enclose a rectangular area of his backyard so his dog can run freely. What is the maximum area,
sdas [7]
Suppose the length of the triangle is x, if the perimeter of the rectangle is 100 ft, the width of the rectangle will be (50-x) ft.
Area of rectangle will be:
A=length*width
A=x(50-x)
A=50x-x^2
at maximum area, dA/dx=0
thus
dA/dx=50-2x=0
solving for x we get
2x=50
x=25
thus for maximum area length=25 ft
the size of the width will be
50-x=50-25=25 ft
thus the maximum area will be:
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5 0
3 years ago
Haley has enlarged a 3-inch by 5-inch picture so that both the length and width are tripled. The area of the enlarged photo is h
77julia77 [94]

Answer:

9 times

Step-by-step explanation:

Area = length x breadth

area of picture not enlarged = 3 x 5 = 15in²

If length is tripled it becomes , 3 x 3 = 9in

If width is tripled, it becomes , 5 x 3 = 15in

Area of enlarged picture = 9in x 15in = 135in²

amount by which enlarged image is larger = 135in² /15in² = 9

5 0
2 years ago
Help please!!!!!!!!!!!!
creativ13 [48]

Answer:

\frac{\pi }{3},\:\frac{2\pi }{3}

Step-by-step explanation:

Let a=THETA (angle)

1+\sin \left(a\right)-1=\frac{\sqrt{3}+2}{2}-1\\\sin \left(a\right)=\frac{\sqrt{3}+2}{2}-1\\a=\arcsin \left(\frac{\sqrt{3}+2}{2}-1\right)+2\pi n,\:a=\pi -\arcsin \left(\frac{\sqrt{3}+2}{2}-1\right)+2\pi n\\a=\frac{\pi }{3},\:a=\frac{2\pi }{3}

7 0
3 years ago
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tamaranim1 [39]
<span>[68,100]

This will allow you to get a B score.

To solve find the medium by adding the values divided by 4, solve for the unknown of the final exam, with the minimum value equalling 80, this will give you 68.</span>
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3 years ago
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