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3 years ago

Give the relevant proportion using correct notation.

Mathematics

1 answer:

nika2105 [10]3 years ago

6 0

Answer:

For this case from the info given we have the estimated proportion of people who thinks that Children of illegal inmigrants should be able to attend public school

So then the value reported 45% or in fraction 0.45 represent the sample proportion fo interest.

$\hat p =\frac{X}{n}=0.45$

And this value was calculated with a sample of n =1000 people.

And X for this case is 450, because 0.45*1000=450

The real interest is on the population proportion $p$ of people who thinks that Children of illegal inmigrants should be able to attend public school

Step-by-step explanation:

Assuming the following question : "Give the relevant proportion using correct notation. Your answer should be an expression composed of symbols: A recent headline states that 45% Think Children of illegal inmigrants Should Be Able to Attend Public School. The report gives the results of a survey of 1000 randomly selected likely voters in the US."

For this case from the info given we have the estimated proportion of people who thinks that Children of illegal inmigrants should be able to attend public school

So then the value reported 45% or in fraction 0.45 represent the sample proportion fo interest.

$\hat p =\frac{X}{n}=0.45$

And this value was calculated with a sample of n =1000 people.

And X for this case is 450, because 0.45*1000=450

The real interest is on the population proportion $p$ of people who thinks that Children of illegal inmigrants should be able to attend public school

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bija089 [108]

Answer:

To answer this question, you need to makes the unit of the smartphone screen same. In this case, phone A is using decimal and phone B is using a fraction. You can use which was easier.

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From here it clear that phone B has a wider screen than phone A.

Step-by-step explanation:

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3 years ago

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Answer:

(4) 29, 33, 37

(6) 53, 59, 65

(5) -16, -20, -24

Step-by-step explanation:

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3 years ago

Folds - Circle Cliffs, UT. Both monoclines and anticlines uplift and deform rock layers such that when eroded, certain ages of r

DIA [1.3K]

Answer:the relative ages of the rocks exposed in the circle cliff area are given below.

1. older rocks are exposed in the center and younger rocks in the flanking flatirons.

2. younger rocks are exposed in the center and older rocks in the flanking flatirons.

Step-by-step explanation: this is because whenever older rocks are exposed in circle cliffs, exposure occur at the center while younger rocks will be exposed in the flanking flatirons at this time.

2. But when younger rocks are exposed in contrast to the older rocks, these younger rocks are exposed at the center while the older ones receive exposure at the flanking flatirons.

Note that both cases interchange, exposure of a particular rock occur at the center and the next category of rock receive theirs at flanking flatirons.

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3 years ago

Order - 11, 22, -10, 17, -26, and 1 from greatest to least.

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3 years ago

What is an example of when you would want consistent data and, therefore, a small standard deviation?

steposvetlana [31]

Answer:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

$\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271$

And for the standard deviation we can use the following formula:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And after replace we got:

$s = 0.1496$

And as we can ee we got a small value for the deviation <1 on this case.

Step-by-step explanation:

For example if we have the following data:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

We see that the data are similar for all the observations so we would expect a small standard deviation

If we calculate the sample mean we can use the following formula:

$\bar X=\frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271$

And for the standard deviation we can use the following formula:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And after replace we got:

$s = 0.1496$

And as we can ee we got a small value for the deviation <1 on this case.

8 0

3 years ago