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kirill115 [55]
4 years ago
6

...................................................

Mathematics
2 answers:
Snezhnost [94]4 years ago
7 0

Answer:

\large \boxed{\sf \bold{A.} \ x=11.21}

Step-by-step explanation:

\large \sf log_3 (x)=2.2

Solve this by converting the logarithmic statement into its equivalent exponential form, using the relationship:

\large \sf log_b(y)=x

\large{\sf y=b^x}

Apply the relationship.

\large \sf log_3 (x)=2.2

\large \sf x=3^{2.2}

\large \sf x=11.21157845...

\large \sf x \approx 11.21

Shalnov [3]4 years ago
5 0

Answer:

11.21157846 =x

Step-by-step explanation:

We know log b (a) = c  can be written as b^c =a

log 3 (x) = 2.2

3^2.2 = x

11.21157846 =x

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