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azamat
2 years ago
11

A calculator was used to perform a linear regression on the values in the table. The results are shown to the right of the table

. What is the line of best fit?

Mathematics
1 answer:
BartSMP [9]2 years ago
5 0

Answer:

the answer is c y=-3.6x+12.8

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Solve for x<br><br> 3(ax + 9) = -4 (-2 - 10x)
ivolga24 [154]

Answer:

19

-----   =   x

40-3a

Step-by-step explanation:

3(ax + 9) = -4 (-2 - 10x)

Distribute

3ax +27 = 8+40x

Subtract 3ax from each side

3ax-3ax +27 = 8+40x-3ax

27 = = 8+40x-3ax

Subtract 8 from each side

27-8 = 8-8+40x-3ax

19 = 40x-3ax

Factor an x on the right side

19 = x(40-3a)

Divide each side by 40-3a

19/(40-3a) = x(40-3a)/(40-3a)

19

-----   =   x

40-3a

8 0
2 years ago
I need to know how to do Solving Systems of Equations by Elimination
vredina [299]
The point of elimination is to have one variable so example

3x + 2y = 4

7X + 3y = 5


1) Try to find a way to have one variable

7(3x + 2y = 4) ----> 21x + 14y = 28

-3(7x+ 3y = 5) -----> -21x -9y = -15


2) add

0 + 5y = 13

3) solve for the last variable

5y = 13
y = 13/5 = 2 3/5 = 2.8

4) Subsitute the variable to get the other one

3x + 2(2.8) = 4

3x + 5.6 = 4

3x = -1.6

x = 0.533333333 (continue)

The intersection would be 0.53 with a line above the 3 and 2.8. (0.5333 , 2.8)

Hope you understand!!
6 0
3 years ago
I NEED A ANSWER ASAP!!
Sveta_85 [38]

Answer:

5

Step-by-step explanation:

5*20=100

7 0
2 years ago
Amira is painting a rectangular banner 2 1/4 yards wide in the cafeteria. The banner will have a blue background. Amira has enou
elena55 [62]
Area of a rectangle:
A = w x h, where w is the width and h is the height.
w = 2.25 yd
A = 1.5 yd²
1.5 = 2.25 · h
h = 1.5 : 2.25 = 0.6667 = 2/3 yd
Answer:
The height of a banner is 2/3 yard.
4 0
3 years ago
Read 2 more answers
A rectangular mat has a length of 12 in. and a width of 4 in. Drawn on the mat are three circles. Each circle has a radius of 2
AVprozaik [17]
Area of the rectangular mat = 12 x 4 = 48 in²

Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²

P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)

Answer: The probability of landing in one of the circles is 0.79.
7 0
2 years ago
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