Consider a 5 molecule system. Assume that the molecules can either be found on the right side or left side of their container.

Chemistry

1 answer:

8090 [49]3 years ago

8 0

Answer:

The correct answer is 6 possible states

Explanation:

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If 1.00 mol of argon is placed in a 0.500-L container at 27.0 degree C , what is the difference between the ideal pressure (as p

ElenaW [278]

Answer:

2.0 atm is the difference between the ideal pressure and the real pressure.

Explanation:

If 1.00 mole of argon is placed in a 0.500-L container at 27.0 °C

Moles of argon = n = 1.00 mol

Volume of the container,V = 0.500 L

Ideal pressure of the gas = P

Temperature of the gas,T = 27 °C = 300.15 K[/tex]

Using ideal gas equation:

$PV=nRT$

$P=\frac{1.00 mol\times 0.0821 L atm/mol K\times 300.15 K}{0.500 L}=49.28 atm$

Vander wall's of equation of gases:

The real pressure of the gas= $p_v$

For argon:

$a=1.345 L^2 atm/mol^2$

b=0.03219 L/mol.

$(p_v+(\frac{an^2}{V^2})(V-nb)=nRT$

$(p_v+(\frac{(1.345 L^2 atm/mol^2)\times (1.00 mol)^2}{(0.500 L)^2})(0.500 L-1.00 mol\times 0.03219L/mol)=1.00 mol\times 0.0821 L atm/mol K\times 300.15 K$