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DIA [1.3K]
3 years ago
10

Consider a 5 molecule system. Assume that the molecules can either be found on the right side or left side of their container.

Chemistry
1 answer:
8090 [49]3 years ago
8 0

Answer:

The correct answer is 6 possible states

Explanation:

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Write a balanced net ionic equation for the following double replacement reaction
shtirl [24]

Answer:

Ba²⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s)  

Explanation:

There are three steps you must follow. You must write the:

  • Molecular equation
  • Ionic equation
  • Net ionic equation

A. Molecular equation

BaCl₂(aq) + Na₂SO₄(aq) ⟶ BaSO₄(s) + 2NaCl(aq)

B. Ionic equation

You write all the soluble substances as ions.

Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)

C. Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

Ba²⁺(aq) + <u>2Cl⁻(aq) </u>+ <u>2Na⁺(aq</u>) + SO₄²⁻(aq) ⟶ BaSO₄(s) + <u>2Na⁺(aq)</u> + <u>2Cl⁻(aq) </u>

The net ionic equation is

Ba²⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s)  

3 0
3 years ago
Challenge question: This question is worth 6 points. As you saw in problem 9 we can have species bound to a central metal ion. T
GenaCL600 [577]

Answer:

CN^- is a strong field ligand

Explanation:

The complex, hexacyanoferrate II is an Fe^2+ specie. Fe^2+ is a d^6 specie. It may exist as high spin (paramagnetic) or low spin (diamagnetic) depending on the ligand. The energy of the d-orbitals become nondegenerate upon approach of a ligand. The extent of separation of the two orbitals and the energy between them is defined as the magnitude of crystal field splitting (∆o).

Ligands that cause a large crystal field splitting such as CN^- are called strong field ligands. They lead to the formation of diamagnetic species. Strong field ligands occur towards the end of the spectrochemical series of ligands.

Hence the complex, Fe(CN)6 4− is diamagnetic because the cyanide ion is a strong field ligand that causes the six d-electrons present to pair up in a low spin arrangement.

5 0
3 years ago
Give the formula of the conjugate base of HSO4–
mr Goodwill [35]
The answer is So^2-4
7 0
3 years ago
How many grams of lithium chloride can be produced from 14.3 g of lithium chlorate when it decomposes into lithium chloride and
vampirchik [111]

6.7 grams of lithium chloride will be produced.

<h3><u>Explanation:</u></h3>

Lithium chlorate is LiClO₃ and lithium chloride is LiCl. The reaction is,

2LiClO₃ = 2LiCl +3O₂.

So here, 2 moles of lithium chlorate produces 2 moles of lithium chloride.

Or, one molecule of lithium chlorate will produce one mole of lithium chloride.

Molecular weight of lithium chlorate =6.9 + 35.5 + 16\times3 = 90.4.

So, 14.3 grams of lithium chlorate has 0.16 moles of lithium chlorate.

Thereby, moles of lithium chloride produced is 0.16 moles.

Molecular weight of lithium chloride = 6.9+35.5 = 42.4 grams.

So weight of lithium chloride produced = 42.4 \times 0.16 = 6.7 grams.

Thus, weight of lithium chloride produced will be 6.7 grams.

3 0
3 years ago
A blacksmith making a tool heats 525 grams of steel to 1230°C. After hammering the steel, she places it into a bucket of water t
Simora [160]
C
WELL HOPE THIS CAN HELP U
6 0
3 years ago
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