Answer:
A: element B
B: element A
C: element B
D: element A
Explanation:
decrease in size leads increase in electronegativity because the smaller the size, the closer the shell is to the nucleus. Also, atomic radius decreases to the right and up on the periodic table. Atomic radius increases to the left and down a period. I hope this helps!
Answer:
Lowering the object near the ground decreases its <u>potential energy.</u>
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Explanation:
Potential Energy : Energy possessed by the object due to its shape ,Size and Position is called potential energy.
Example :
Change in shape and size : When you compress the spring , potential energy is introduced in it . So it expand quickly when you remove your hand.
Change in position : when you swing , after attaining maximum height (extreme ends) , the swing comes back on its on .This is because at maximum height ,the swing has<u> maximum Potential energy . </u>Hence it fall back on its on because it already has potential energy.
Potential energy(P) is given by the formula :
P = mgh
where ,
m= mass of the object
g = acceleration due to gravity
h = height of the object from the ground
If the height of the object increases from the ground , its potential energy also get increase.
<u><em>On lowering the object The height of the object from the ground reduces . So potential energy also reduces.</em></u>
The balanced equation for reaction of solid cesium with liquid water
= 2Cs + 2H2O → 2CsOH + H2
cesium react with liquid water to produce cesium hydroxide and hydrogen gas
that is 2 moles of Cs react 2 moles of H2O to form 2 moles CsOH and 1 of hydrogen gas
Q1)
firstly we need to determine the empirical formula of the compound. empirical formula is the simplest ratio of components in the compound.
percentages of the elements have been given, so lets assume we are calculating for a compound of 100g
C H O
mass 63.13 g 8.830 g 28.03 g
molar mass 12 g/mol 1 g/mol 16 g/mol
number of moles 63.13/12 8.830/1 28.03/16
5.26 8.830 1.75
divide by the smallest number of moles
5.26/1.75 8.830/1.75 1.75/1.75
= 3.01 = 5.04 =1
rounded off to the nearest whole numbers
C - 3
H - 5
O - 1
therefore empirical formula = C₃H₅O
Q2)
we have to next determine the molecular formula of the compound
molecular formula gives the actual composition of elements in the compound.
since we know the empirical formula and molecular mass, we can find how many empirical units are in the molecular formula.
mass of empirical unit = Cx3 + Hx5 + Ox1
= 12 g/mol x 3 + 1g/mol x 5 + 16 g/mol x 1
= 36 + 5 + 16 = 57 g/mol
the molecular mass = 228 g/mol
then number of empirical units in the molecular formula = 228 / 57 = 4
therefore there are 4 empirical units
then the molecular formula = 4 x empirical formula =4 (C₃H₅O)
molecular formula = C₁₂H₂₀O₄
