Find the value of X plsss help!!

Mathematics

1 answer:

denis-greek [22]2 years ago

5 0

Answer: B

The Vertical Angles Theorem states that vertical angles, angles that are opposite each other and formed by two intersecting straight lines, are congruent. This means that 48° should equal (7x+13)°, because they're vertical angles. The equation should appear as 48=7x+13. Subtract 13 on both sides to get. 35=7x. Divide 7 on both sides to result with x=5.

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Given: BDis a diameter m 1 = 100° m BC= 30° m2 = 30 80 100

skad [1K]

Answer:

∠2 = 80°

Step-by-step explanation:

Since BD is a diameter then

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100° + ∠2 = 180° ( subtract 100° from both sides )

∠2 = 180° - 100° = 80°

4 0

3 years ago

Read 2 more answers

Terry wants to divide his 120 baseball cards into two groups, so that the ratio of the number of cards in the first group to the

Naddik [55]

Let the number of cards in each group be 2x and 3x.
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3 years ago

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$