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zhenek [66]
3 years ago
5

Why is there a need for increased recycling to preserve phosphorus

Chemistry
1 answer:
sesenic [268]3 years ago
5 0

Answer:

The phosphorus minerals deposits that are available right now are not enough for the future. A large part of food production depends on phosphorus being produced. Phosphorus is commonly used as fertilizer and a lot of farmers are dependent on it.

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A gas occupies 3.8 L at -18° C and 975. torr. What volume would this gas occupy at STP?
Aleks04 [339]

To solve the question we will assume that the gas behaves like an ideal gas, that is to say, that there is no interaction between the molecules. Assuming ideal gas we can apply the following equation:

PV=nRT

Where,

P is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is a constant

T is the temperature

Now, we have two states, an initial state, and a final state. The conditions for each state will be.

Initial state (1)

P1=975Torr=1.28atm

V1=3.8L

T1=-18°C=255.15K

Final state(2), STP conditions

P2=1atm

T2=273.15K

V2=?

We will assume that the number of moles remains constant, so the nR term of the first equation will be constant. For each state, we will have:

\begin{gathered} \frac{P_1V_1}{T_1}=nR \\ \frac{P_2V_2}{T_2}=nR \end{gathered}

Since nR is the same for both states, we can equate the equations and solve for V2:

\begin{gathered} \frac{P_{2}V_{2}}{T_{2}}=\frac{P_1V_1}{T_1} \\ V_2=\frac{P_{1}V_{1}}{T_{1}}\times\frac{T_2}{P_2} \end{gathered}

We replace the known values:

V_2=\frac{1.28atm\times3.8L}{255.15K}\times\frac{273.15K}{1atm}=5.2L

At STP conditions the gas would occupy 5.2L. First option

8 0
1 year ago
Can someone help me with this please
Nuetrik [128]
When the temperature increases the atoms gain energy and the substance changes into a gas state.
The is the opposite when the temperature decreases and the liquid becomes solid ( in this case ice).
3 0
3 years ago
Wertyujikl;lkmjnbvcdsdertyuikmnbvcxs sdfrtyuiolkmnbvcxzasedrty hgrewazxcvbn
alina1380 [7]

Answer:

ndndjdndn

Explanation:

nxjfnthfnrnrld

4 0
3 years ago
Read 2 more answers
If a 22.4 L volume of a sample of gas has a density of 0.900 grams/L at 1.00 atm and 0.00°C. Given
disa [49]

Answer:

Formula Weight of gas sample = 20.1 g/mole => Neon (Ne)

Explanation:

Use Ideal Gas Law formula to determine formula weight and compare to formula weights of answer choices.

PV = nRT = (mass/fwt)RT => fwt = (mass/Volume)RT = Density x R x T

Density = 0.900 grams/L

R = 0.08206 L·atm/mole·K

T = 0.00°C = 273Kfwt = (0.900g/L)(0.08206L·atm/mole·K )(273K)

= 20.1 g/mol => Neon (Ne)

4 0
3 years ago
What is milliliter the same as?
Klio2033 [76]

Answer:

1 cubic centimeter

Explanation:

8 0
3 years ago
Read 2 more answers
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