From the information in the question, the E° and E for the cell is 0.00 V and 0.12 V.
Using the Nernst equation;
Ecell = E°cell - 0.0592/n log Q
We know that E°cell = 0.00 V since the anode and cathode are both made up of cadmium.
Substituting the given values into the Nernst equation;
Ecell = 0.00 V - 0.0592/2 log (1.0 × 10-5 M/0.100 M)
Ecell = 0.00 V - 0.0296 log(1 × 10^-4)
Ecell = 0.12 V
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Answer:
it again form new blood and this process is very fast process . our bone marrow form the RBC within one day ,that we loosed
I'm not sure but I think it is C. CrO3
Answer:
Mass = 46.52 g
Explanation:
Given data:
Mass of sodium phosphate react = 49.33 g
Mass of calcium phosphate produced = ?
Solution:
Chemical equation:
2Na₃PO₄ + 3Ca(NO₃)₂ → Ca₃(PO₄)₂ + 6NaNO₃
Number of moles of Na₃PO₄:
Number of moles = mass/molar mass
Number of moles = 49.33 g/ 163.94 g/mol
Number of moles = 0.300 mol
now we will compare the moles of Na₃PO₄ and Ca₃(PO₄)₂
Na₃PO₄ : Ca₃(PO₄)₂
2 : 1
0.300 : 1/2×0.300 = 0.15
Mass of Ca₃(PO₄)₂:
Mass = number of moles × molar mass
Mass = 0.15 mol × 310.14 g/mol
Mass = 46.52 g
