Both of these problems will be solved in a similar way, but with different numbers. First, we set up an equation with the values given. Then, we solve. Lastly, we plug into the original expressions to solve for the angles.
[23] ABD = 42°, DBC = 35°
(4x - 2) + (3x + 2) = 77°
4x+ 3x + 2 - 2 = 77°
4x+ 3x= 77°
7x= 77°
x= 11°
-
ABD = (4x - 2) = (4(11°) - 2) = 44° - 2 = 42°
DBC = (3x + 2) = (3(11°) + 2) = 33° + 2 = 35°
[24] ABD = 62°, DBC = 78°
(4x - 8) + (4x + 8) = 140°
4x + 4x + 8 - 8 = 140°
4x + 4x = 140°
8x = 140°
8x = 140°
x = 17.5°
-
ABD = (4x - 8) = (4(17.5°) - 8) = 70° - 8° = 62°
DBC =(4x + 8) = (4(17.5°) + 8) = 70° + 8° = 78°
Answer:
the answer is b
Step-by-step explanation:
just got it right on my laptop :)
Step-by-step explanation:
3. The triangle that makes up the square is a 45-90-45 triangle so x = 45°. Using Pythagorean theorem,
2y^2 = 12 ---> y^2 = 6
or
y = √6
4.This is an equilateral triangle of side 11 so
y = 11/2
To find x, use the definition of sine 60:
sin 60° = opp/hyp
= x/11
or
x = 11sin60° = (11√3)/2
Answer:
Your answer is 4x.
Step-by-step explanation:
Add 2+2
Combine your x's (like terms)
then you got 4 from 2+2
Add the leftover x so it makes 4+x then add it will give you 4x.