3 years ago

F(x)=x^2+x-2 and g(x)=3x-1 Find (f+g)(1)=

1 answer:

Dimas [21]3 years ago

7 0

$( {x}^{2} + x - 2) + (3x - 1) \\ {x}^{2} + 4x - 3 \\ {1}^{2} + 4(1) - 3 \\ 1 + 4 - 3 \\ 2$

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tatyana61 [14]

The last one is correct

3 0

3 years ago

Artist 52 [7]

Answer:

Step-by-step explanation:

8(3x - 6) = 6(4x + 8)

24x - 48 = 24x + 48

24x - 24x = 48 + 48

0 ≠ 96

this will have NO SOLUTIONS....because no matter what value u put in for x, they will never be equal.

3 0

3 years ago

Archy [21]

I believe the correct situation is C

3 0

3 years ago

lord [1]

ANSWER:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(−2,−16)

Equation Form:

x= −2, y= −16

8 0

3 years ago

AleksandrR [38]

<span>divide the numerator by the denominator to find its decimal equivalent.</span>

6 0

3 years ago