Describe the one basic move you need to change the equation

What is 30 times 2 hi someone please answer this pls

Sedbober [7]

Answer:

60

Step-by-step explanation:

yeppp

4 0

4 years ago

This is math( Can you help me please?

kherson [118]

Answer:

f(x) = 17x +17

136 in

Step-by-step explanation:

Changing the number of boxes by 1 changes the stack height by 17 inches, so the arithmetic sequence can be written as

... f(x) = x₁ +d(x -1)

The first term is shown to be 34, so the function is

... f(x) = 34 +17(x -1)

This can be simplified to ...

... f(x) = 17x +17

_____

From 1 box to 4 boxes (addition of 3 boxes), the height changed from 34 in to 85 in (addition of 51 in).

Adding 3 more boxes to make 7 boxes in the stack should add 51 more inches:

... 85 in + 51 in = 136 in

___

The problem statement tells you to use the above function to solve the problem, so ... (put 7 where x is, then do the arithmetic)

... f(7) = 17·7 +17 = 119 +17 = 136 . . . inches

8 0

4 years ago

You are given four balls. 2 red and 2 blue. You are asked to draw one ball each time from the box. Before your draw, you need to

rjkz [21]

Answer:

At every pick the probability may vary depending upon your guess is right or wrong.

Step-by-step explanation:

First pick:

Equal probability for both red and blue = 1/2

Second pick:

case 1: If first pick was red.

then predict blue because the probability of blue exceeds the probability of red.

P(b) = 2/3

P(r) = 1/3

case 2: if first pick was blue.

then predict red because the probability of red exceeds the probability of blue.

P(r) = 2/3

P(b) = 1/3

Third pick:

case 1: R,B

then predict either red or blue due to equal probabilities.

note: Similar case for B,R.

case 2: RR

then obviously you will predict blue because P(b)=1 and vice versa for the case if the first two draws were BB.

Fourth Pick:

Fourth pick would be obvious because you are left with only remaining colored ball for which the probability must be 1.

6 0

3 years ago

Changing percentages as decimal change the following into decimal places 20% , 30%, 25%, 16%

Tasya [4]

20%=0.2
30%=0.3
25%=0.25
16%=0.16

5 0

4 years ago

Read 2 more answers

Hallmark would like to test the hypothesis that those celebrating Valentine's Day will spend more than an average of $125 on gif

Vaselesa [24]

Answer:

We conclude that those celebrating Valentine's Day spend more than an average of $125 on gifts.

Step-by-step explanation:

We are given that Hallmark would like to test the hypothesis that those celebrating Valentine's Day will spend more than an average of $125 on gifts.

A random sample of 18 people celebrating Valentine's Day spent an average of $148.50 with a standard deviation of $34.90.

Let $\mu$ = average amount spent on gifts celebrating Valentine's Day

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ $125 {means that those celebrating Valentine's Day spend less than or equal to an average of $125 on gifts}

Alternate Hypothesis, $H_A$ : $\mu$ > $125 {means that those celebrating Valentine's Day spend more than an average of $125 on gifts}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average amount spent = $148.50

s = sample standard deviation = $34.90

n = sample of people = 18

So, test statistics = $\frac{148.50-125}{\frac{34.90}{\sqrt{18} } }$ ~ $t_1_7$

= 2.857

The value of the sample test statistics is 2.857.

Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_1_7$ > 2.857) = 0.0056

Because in the t table the critical value of 2.857 at 17 degree of freedom will lie between P = 1% and P = 0.5%.

Now, since P-value of test statistics is less than the level of significance as 0.01 > 0.0056, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that those celebrating Valentine's Day spend more than an average of $125 on gifts.

3 0

3 years ago