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k0ka [10]
3 years ago
8

The average score on a national assessment test for a subject was 194 points for​ fourth-graders who studied the subject about 4

5 minutes per week. The average score was 211 points for​ fourth-graders who studied the subject about 150 minutes per week. There is an approximate linear relationship between the number of hours​ fourth-graders study the subject per week and the average score on the test. Estimate the average score for​ fourth-graders who study the subject about 235 minutes per week.
Mathematics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:

The average score for​ fourth-graders who study the subject about 235 minutes per week is 224.76.

Step-by-step explanation:

Let x be the number of hours​ fourth-graders study the subject per week and y be the average score on the test. It is given that there is an approximate linear relationship between x and y.

It is given that the average score on a national assessment test for a subject was 194 points for​ fourth-graders who studied the subject about 45 minutes per week. It means the line passes through (45, 194).

The average score was 211 points for​ fourth-graders who studied the subject about 150 minutes per week. It means the line passes through (150, 211).

If a line passes through two points then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of required line is

y-194=\frac{211-194}{150-45}(x-45)

y-194=\frac{17}{105}(x-45)

Using distributive property,

y-194=\frac{17}{105}(x)-\frac{17}{105}(45)

y-194=\frac{17}{105}(x)-\frac{51}{7}

Add 194 on both sides.

y=\frac{17}{105}(x)-\frac{51}{7}+194

y=\frac{17}{105}(x)+\frac{1307}{7}

Substitute x=235 in the above equation.

y=\frac{17}{105}(235)+\frac{1307}{7}

y=\frac{799}{21}+\frac{1307}{7}

y=\frac{4720}{21}

y=224.7619

y\approx 224.76

Therefore the average score for​ fourth-graders who study the subject about 235 minutes per week is 224.76.

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I need 20 characters idk why, but I need a step by step explanation 5y-3(2-y)=10​
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Solve for y:

5y-3(2-y)=10​

Distribute the -3 to the variables inside the parenthesis.

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4 years ago
Solve by the matrix method , x+y/5 -1=y-x​
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10x - 4y = 5 (if it requires shorten)

Step-by-step explanation:

x + y/5 - 1 = y - x

<=> (5x + y - 1.5)/5 = 5(y - x)/5

<=> 5x + y - 5 = 5y - 5x

<=> 5x + 5x + y - 5y = 5

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6 0
3 years ago
The population standard deviation for the temperature of beers found in Scooter's Tavern is 0.26 degrees. If we want to be 90% c
siniylev [52]

Answer:

19 beers must be sampled.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The population standard deviation for the temperature of beers found in Scooter's Tavern is 0.26 degrees.

This means that \sigma = 0.26

If we want to be 90% confident that the sample mean beer temperature is within 0.1 degrees of the true mean temperature, how many beers must we sample?

This is n for which M = 0.1. So

M = z\frac{\sigma}{\sqrt{n}}

0.1 = 1.645\frac{0.26}{\sqrt{n}}

0.1\sqrt{n} = 1.645*0.26

\sqrt{n} = \frac{1.645*0.26}{0.1}

(\sqrt{n})^2 = (\frac{1.645*0.26}{0.1})^2

n = 18.3

Rounding up:

19 beers must be sampled.

7 0
3 years ago
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