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marusya05 [52]
3 years ago
11

Answer these please!!!!!

Mathematics
1 answer:
garik1379 [7]3 years ago
3 0
4.
-3/4 - 2/3 ÷ (-4/5)
= -3/4 - [2/3 ÷ (-4/5)]
{switch the numerator and denominator when changing from ÷ to ×, or × to ÷}
= -3/4 - [2/3 × (-5/4)]
{numerator × numerator, and denominator × denominator}
= -3/4 - [-10/12]
= -3/4 + 10/12
= -9/12 + 10/12
= 1/12

5.
-2 2/5 + (-2 4/5) × 4/7
= -2 2/5 - (2 4/5 × 4/7)
= -12/5 - (14/5 × 4/7)
= -12/5 - (56/35)
{Simplify fraction to make denominators same}
= -12/5 - (8/5)
= -20/5
= -4/1
= -4

6.
-(-3/5) - 1 3/7 ÷ (-5/14)
{Negative signs cancelled out, fractions compounded}
= 3/5 - 10/7 ÷ (-5/14)
{Switch numerator and denominator when switch from ÷ to ×}
= 3/5 - [10/7 × (-14/5)]
= 3/5 - [-140/35]
= 3/5 + 20/5
= 23/5
{Simplify fraction}
= 4 3/5

Hope this helps! :) You may ask me for more help if you need
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Step-by-step explanation:

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Three sisters want to.Buy a pda for their fauther for fauthers day. The least expensive pda in the sorr isn$360. Writenand slove
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$120

Step-by-step explanation:

I would like to rewrite your question for others easy to understand:

<em>"Three sisters want to Buy a pda for their father for fathers' day. The least expensive pda in the store  is $360. Writen and slove an inequality to fund the least amout of money each girl would have ti contrubute if each contribute an equal amount" </em>

<em />

Let X is the the amount one girl contribute, we have 3 girls => 3X

The least expensive pda in the store  is $360, so the total contributed amount must be equal or smaller than the pda cost

<=> 3X  \leq 360

<=> X \leq 120

So the least amout of money each girl would have to contrubute is $120

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Find x and y using subsitution<br><br> -3x + y = 6<br> 5x + 2y =23
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\left\{\begin{array}{ccc}-3x+y=6&|\text{add 3x to both sides}\\5x+2y=23\end{array}\right\\\\\left\{\begin{array}{ccc}y=3x+6\\5x+2y=23\end{array}\right\\\\\text{substitute}\ y=3x+6\ \text{to the second equation}\\\\5x+2(3x+6)=23\qquad|\text{use distributive property}\\\\5x+(2)(3x)+(2)(6)=23\\\\5x+6x+12=23\qquad|\text{subtract 12 from both sides}\\\\11x=11\qquad|\text{divide both sides by 11}\\\\\boxed{x=1}\\\\\text{subtract the value of x to the first equation}\\\\y=3(1)+6\\\\y=3+6\\\\\boxed{y=9}

<h3>Answer: x = 1 and y = 9 → (1, 9).</h3>
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3 years ago
Read 2 more answers
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