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Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Dahasolnce [82]

Note: you may have unintentionally missed to add the complete question. Therefore, after a little research, I am able to find the complete question which I am attaching to solve your query, which anyways would clear your concept.

The complete Question:

Keenan gives Tisha half of his strawberries. Tisha keeps 4 of the strawberries she got from Keenan and gives the rest to Suvi.

a) Write an expression for the number of strawberries Tisha gives to Suvi. Use k for the number of strawberries Keenan started with.

b) Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Answer:

Part a)

An expression for the number of strawberries Tisha gives to Suvi will be: $n=\frac{k}{2} -4$

Part b)

Keenan could not have started with 6 strawberries

Step-by-step explanation:

Part a) Write an expression for the number of strawberries Tisha gives to Suvi. Use k for the number of strawberries Keenan started with.

Let $k$ be the total number of strawberries which Keenan has.

So,

$\frac{k}{2}$ is the number of strawberries Keenan gave to Tisha.

As Tisha keeps 4 strawberries and gives the rest to Suvi. Let $n$ be the number of strawberries which Suvi has.

So,

$n=\frac{k}{2} -4$

$\frac{k}{2}=n+4$

$k=2n+8$

Therefore, an expression for the number of strawberries Tisha gives to Suvi will be: $n=\frac{k}{2} -4$

b) Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Considering the expression for the number of strawberries Tisha gives to Suvi

$n=\frac{k}{2} -4$

Putting $k = 6$ in the expression

$n=\frac{6}{2} -4$

Solving the expression

$n=3-4$ ∵ $\mathrm{Divide\:the\:numbers:}\:\frac{6}{2}=3$

$\mathrm{Subtract\:the\:numbers:}\:3-4=-1$

$n=-1$

So, Keenan would have started with 6 strawberries, then Suvi would have -1 strawberries. Since, strawberries cannot be negative as Suvi cannot have negative number of strawberries.

Therefore, Keenan could not have started with 6 strawberries.

Keywords: word problem, expression

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3 years ago

1. Darnell reads at a constant rate

JulsSmile [24]

Answer:

Darnell can read 1,715 words in 7 minutes

Step by step Explanation:

1. I need to find out how many words he reads in 1 minute. Divide 735 by 3, my answer is 245

245

______

3)735

6 bring down the 3 to make 13

-_____

1 3

12 bring down the 5 to make 15

-______

1 5

15

___________

0

2. multiply 735 by 2 cause he reads 735 words in 3 minutes and we are tryna find out how many words he reads in 7 minutes. 3×2=6, so 735+735 (735×2) equals 1470

3. Add 245, for that extra minute that we missed. my answer is 1,715 words in 7 minutes

8 0

3 years ago

*If you add two integers with different signs, how can you tell whether the sum will be positive, negative, or zero?

irina [24]

Answer:

Please see explanation

Step-by-step explanation:

When two integers are being added there can be three cases in the answer

Positive

The sum will be positive if both the integers are positive and in case of addition of one positive and negative integer, the sum will be positive if the integer with larger magnitude is positive

Negative

The sum will be negative if both integers are negative and in case of addition of one positive and negative integer, the sum will be negative if the integer with larger magnitude is negative

Zero

The sum will be zero if both the integers have same magnitude and different signs.

7 0

3 years ago

Determine whether the series is arithmetic or geometric. Then evaluate the finite series for the specified number of terms. 10 +

Salsk061 [2.6K]

Answer:

10 + 7 + 4 + . . .; n = 5

The series is arithmetic

Common difference between terms = (-3)

10 - 3 = 7

7 - 3 = 4

Or:

10 + (-3) = 7

7 + (-3) = 4

--------------------------------------------------------------------------

Another example:

Arithmetic:

5, 9, 13, 17

common difference = 4

5 + 4 = 9

9 + 4 = 13

Geometric:

4, 8, 16, 32

4 × 2 = 8

8 × 2 = 16

16 × 2 = 32

common ratio = 2

--------------------------------------------------------------------------

10 + 7 + 4 + . . .; n = 5

a₁ = 10

a₂ = 7

a₄ = a₃ + d = 4 + (-3) = 4 - 3 = 1 (d = common difference)

a₅ = a₄ - 3 = 1 - 3 = -2

Or with formula:

$d=a_{n} -a_{n-1}$

d = a₂ - a₁ = 7 - 10 = -3

aₙ = a₁ + (n - 1)d

fourth term = a₄ = 10 + (4 - 1)(-3) = 10 + 3(-3) = 10 + (-9) = 10 - 9 = 1

fifth term = a₅ = 10 + (5 - 1)(-3) = 10 + 4(-3) = 10 + (-12) = 10 - 12 = -2

Sum of the finite series (if n = 5):

$S_{n} =\frac{n(a_{1} +a_{n} )}{2} \\S_{5} =\frac{5(a_{1} +a_{5} )}{2} \\S_{5} =\frac{5(10 +(-2) )}{2} \\S_{5} =\frac{5(8 )}{2} =\frac{40}{2} =20$

Manual count: S₅ = 10 + 7 + 4 + 1 + (-2) = 20

7 0

2 years ago

Find the equation for an exponential function that passes through the pair of points given below. (Round all coefficients to 4 d

ollegr [7]

Answer: f(x) = 2(3^x)

Step-by-step explanation:

7 0

3 years ago