Lim ln([(x+1)/x]^3x) as x ->.infinity =lim ln([(x+1)^(3x)]/[x^(3x)]) as s->infinity =lim ln((x+1)^(3x))-ln(x^(3x)) = infinity - infinity
your answer is e3 but you can use l'hopital if you liketake the log, get 3xln(1+1/x)which is in the form ∞×0 then use the usual trick of rewriting as ln(1+1/x)/1/3x
Answer:
184960
Step-by-step explanation:
1445 x 128 = 184960
7-4 (d-3)=23
7-4d+12=23 **multiply -4 with (d-3)***
7+12-4d=23
19-4d=23
-4d=23-19
-4d=4
d=4÷-4
d= -1
17.06. 17.07 if you round up
Answer:
The answer to your question is 
Step-by-step explanation:
Data
cos Ф = 3/5
tan2Ф = ?
Quadrant IV
Process
1.- Remember that tanФ =
and cos Ф = 
then, adjacent side = 3 and hypotenuse = 5
2.- Calculate opposite side
O² = h² - a²
O² = 5² - 3²
O² = 25 - 9
O² = 16
O = 4
3.- Calculate the tan 2Ф
tan 2Ф = 2(
) The opposite side is negative in the fourth
quadrangle
tan 2Ф = 