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Svet_ta [14]
4 years ago
5

Solve each of the following equations for x showing the algebra you used to do it. Round each answer to the nearest ten-thousand

s place.
11. 7^(x-3)=25

12. log (3x+1)

13. log(7x+1) = log(x-2) +1

14. 4e^(2x)-3=12

If you can't answer all of them that's totally fine. Thank you! ☻♥
Mathematics
1 answer:
lyudmila [28]4 years ago
4 0
11)46/7 thats the answer
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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
4 years ago
Read 2 more answers
*Will mark brainest!!* Write an equation in point slope form <br> (-9,7) m=4
pshichka [43]

Answer:

y-7 = 4(x+9)

Step-by-step explanation:

Point slope form is

y-y1 = m(x-x1)

where m is the slope and (x1,y1) is the point

y-7 = 4(x--9)

y-7 = 4(x+9)

4 0
4 years ago
Ok whoever answers this correct will get 100 brainly points
Snezhnost [94]

Answer:

We are given an area and three different widths and we need to determine the corresponding length and perimeter.  

The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards.  This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.

The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards.  This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.

The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10.  This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.

Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.

<u><em>Hope this helps!</em></u>

3 0
2 years ago
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"blank" are the products of the smaller problems in the place value rows methed
Talja [164]

Answer:

hindi sulotion kung hindi man sorry nalang

walarin akong alam diyaan

Step-by-step explanation:

im sosory

8 0
3 years ago
A picture has an area of 35cm and is 7cm long.An enlargement of the picture is made is 21cm long.Find the area of the enlargemen
marta [7]

Answer: The area of the enlargement is 315cm.

Step-by-step explanation:

If the picture has 35cm as the area and it has a length of 7cm  then we can find the width by dividing the area by the length.

w= 35/7

w =  5      

So in this care the width of the picture in 5cm.

Now is saying that the picture's length has been enlarge or been dilated to 21 cm. To get from 7cm to 21cm you will have to multiply  by 3.  

In this situation, we will have to multiply the original picture's width by 3 to find it enlargement.

w= 5*3 = 15  

The width is 15cm and the length is 21cm so multiply them to find the area.

A = 15 * 21

A = 315cm

6 0
3 years ago
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