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dlinn [17]
2 years ago
6

PLEASE HELPPPP THIS IS A VERY IMPORTANT AND IM STUCK

Mathematics
1 answer:
Ronch [10]2 years ago
4 0

Answer:

73=7x+38

35=7x

x=5

180-73 = 107

z=107

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What multiple of 8 gets an equal multiple of 9
musickatia [10]

Answer:

72

Explanation:

8*9=72

5 0
3 years ago
BC = 36; D = 15. What is the value of BD - AC.<br> B<br> A<br> BD - AC =
Snezhnost [94]

Answer:

BD - AC = 0

Step-by-step explanation:

Given that:

BC = 36 , CD = 15 and BD = x

As these are forming right angled triangle,

Using Pythagorean theorem,

(BD)^2+(CD)^2=x^2\\(36)^2+(15)^2 = x^2\\1296 + 225 = x^2\\1521 = x^2\\

Taking square root on both sides

\sqrt{x^2}=\sqrt{1521}\\x=39

As the given shape is rectangular, the sides parallel to each other will have same values.

AB = 15 , AD = 36 and AC = x

(15)^2+(36)^2 = x^2 \\225 + 1296 = x^2 \\1521 = x^2 \\x = 39

Now,

BD - AC = 39 - 39 = 0

Hence,

BD - AC = 0

5 0
3 years ago
Help me i don'tunderstand please
PIT_PIT [208]

Step-by-step explanation:

using SOH CAH TOA.

h=3.46 and b=4.42

4 0
2 years ago
Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

3 0
2 years ago
Given: Circumscribed ABCD, AB=5,<br><br>AD=8, CD=10.<br><br> Find: BC
Lyrx [107]

Answer:

BC=7

Step-by-step explanation:

The circle can be circumscribed into the quadrilateral, if the sums of the opposite sides of the quadrilateral are eqaul.

Thus,

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5 0
3 years ago
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