Answer:
It's position at time t = 5 is 593.
Step-by-step explanation:
The velocity v(t) is the integral of the acceleration a(t)
The position s(t) is the integral of the velocity v(t)
We have that:
The acceleration is:

Velocity:

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13
Then

Position:

Since s(0) = 3

What is its position at time t=5?
This is s(5).



It's position at time t = 5 is 593.
First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.
If we need the vertex to be at
, the equation will contain a
term.
If we start with
we have a parabola, concave down, with vertex at
and a maximum of 0.
So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be 
We have

Now we only have to fix the fact that this parabola doesn't land at
, because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want

such that:
Plugging these values gets us

As you can see in the attached figure, the parabola we get satisfies all the requests.
Answer: sqrt(2)/2 which is choice D
======================================================
Explanation
(3pi/4) radians converts to 135 degrees after multiplying by the conversion factor (180/pi).
The angle 135 degrees is in quadrant 2. We subtract the angle 135 from 180 to find the reference angle
180-135 = 45
Then you can use a 45-45-90 triangle to determine that the ratio of opposite over hypotenuse is sqrt(2)/2
sine is positive in quadrant 2
------------
Alternatively, you can use a unit circle. Refer to the diagram below. In red, I've circled the angle 3pi/4 radians. The terminal point for this angle has a y coordinate of sqrt(2)/2
Recall that y = sin(theta).
Answer:
1.)no
2.)yes
3.)yes
4.)no
5.)yes
6.)no
7.)yes
8.)yes
9.)no
10.)no
11.)yes
12.)yes
13.)yes
14.)no
15.)no
16.)yes
17.)no
18.)yes
19.)no
20.)no
21.)yes
22.)yes
23.)yes
24.)yes
Step-by-step explanation:
i hope that helps..