Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
Answer:
92
Step-by-step explanation:
92+88= 180 all suplementtary angles =180
Answer:
No solutions
Step-by-step explanation:
|-2x-10| + 4 = 2
Subtract 4 from each side
|-2x-10| + 4-4 = 2-4
|-2x-10| = -2
The absolute value is negative so there are no solutions.
Absolute values are always positive, so they cannot be negative.
Answer:
???ummm no details
Step-by-step explanation:
There’s this website you can search on your phone/laptop called Desmos
