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Anuta_ua [19.1K]
4 years ago
12

HELP !! I NEED SOMEONE TO DO THIS TO ME!!

Mathematics
1 answer:
yKpoI14uk [10]4 years ago
4 0

Answer:

The LCM of 63 and 91 is 819

Explanation:

1) Find the prime number of 63

63 = 3 × 3 × 7

2) Find the prime number of 91

91 = 7 × 13

3) Multiply each factor the greater number of times it occurs in steps or above to find the LCM:

LCM = 3 × 3 × 7 × 13

<u>4)</u><u> LCM = 819</u>

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Step-by-step explanation:

4. h(x) = 2x^2 + 14x - 60

Step-by-step explanation:

Given that h(x) is a quadratic.

Also, h(3) = h(-10) = 0

(A) h(x) = x^2 - 13x - 30

=> h(3) = 3^2 - 13(3) - 30

=> h(3) = 9 - 39 - 30

=> h(3) = -30 - 30

=> h(3) = -60

=> h(3) ≠ 0

(B) h(x) = x^2 - 7x - 30

=> h(3) = 3^2 - 7(3) - 30

=> h(3) = 9 - 21 - 30

=> h(3) = -12 - 30

=> h(3) = -42

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(C) h(x) = 2x^2 + 26x - 60

=> h(3) = 2(3^2) + 26(3) - 60

=> h(3) = 2(9) + 78 - 60

=> h(3) = 18 + 78 - 60

=> h(3) = 96 - 60

=> h(3) = 36

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(D) h(x) = 2x^2 + 14x - 60

=> h(3) = 2(3^2) + 14(3) - 60

=> h(3) = 2(9) + 42 - 60

=> h(3) = 18 + 42 - 60

=> h(3) = 60 - 60

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And

=> h(-10) = 2(-10)^2 + 14(-10) - 60

=> h(-10) = 2(100) - 140 - 60

=> h(-10) = 200 - 200

=> h(-10) = 0

Clearly we have,

=> h(3) = h(-10) = 0

Hence, the correct option is (D) h(x) = 2x^2 + 14x - 60

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