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Anuta_ua [19.1K]
4 years ago
12

HELP !! I NEED SOMEONE TO DO THIS TO ME!!

Mathematics
1 answer:
yKpoI14uk [10]4 years ago
4 0

Answer:

The LCM of 63 and 91 is 819

Explanation:

1) Find the prime number of 63

63 = 3 × 3 × 7

2) Find the prime number of 91

91 = 7 × 13

3) Multiply each factor the greater number of times it occurs in steps or above to find the LCM:

LCM = 3 × 3 × 7 × 13

<u>4)</u><u> LCM = 819</u>

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Please help!!<br><br> Write an equation for the line on the graph above:
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-1 = 1x

Step-by-step explanation:

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Pythagorean triplets of 26​
Black_prince [1.1K]

Answer:

10,24,26

Answer step by step:

  • Phytagorean Theorem

The Pythagorean Theorem is a useful tool that shows how the sum of the areas of three intersecting squares can determine the side lengths of a right triangle.

  • Phytagorean Formula

\large{ \boxed{c =  \sqrt{ {a}^{2} +  {b}^{2}  }} }

With:

c = hypotenusa

a = upright side

b = pedestal side

Keep in mind that the Pythagorean formula only applies to right-angled triangles

  • Continue to discussion

26 =  \sqrt{ {10}^{2} +  {24}^{2}  }

26 =  \sqrt{(10 \times 10) + (24 \times 24)}

26 =  \sqrt{100 + 576}

26 =  \sqrt{676}

26 =  \sqrt{26 \times 26}

26 =  \sqrt{ {26}^{2} }

26 = 26

conclusion that prove that 10,24,26 is a Pythagorean triple.

  • Learn More About Phytagorean Theorm

How do I figure the pythegeroen theorm(brainly.com/question/12919358)

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8 0
2 years ago
Consider the function f(x)=10^x and function g.
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C, graph transformation rules
6 0
3 years ago
A rectangular piece of plywood has a diagonal which measures two feet more than the width. The length of the plywood is twice th
Nina [5.8K]

Answer:

The length of the diagonal = 3.6 feet

Step-by-step explanation:

* Lets change the story problem to equation to solve it

- Diagonal in a rectangle is the line which joining two

 opposite vertices in it

- The diagonal , the length and the width formed together right

  angle triangle where the diagonal is the hypotenuse of the

  triangle and the length, the width are the two legs of the

  right angle

- The length of the diagonal d is √(l² + w²) ⇒ Pythagoras theorem

∴ d² = l² + w²

- The diagonal is 2 feet more than the width

∴ d = w + 2

- The length is twice the width

∴ l = w

* Lets substitute the value of d and l in the equation of Pythagoras

∴ (w + 2)² = (2w)² + w² ⇒ solve the bracket

∴ w² + 4w + 4 = 4w² + w² ⇒ collect them in one side and add like term

∴ 4w² + w² - w² - 4w - 4 = 0 ⇒ add the like term

∴ 4w² - 4w - 4 = 0 ⇒ divide all term by 4

∴ w² - w - 1 = 0 ⇒ solve the quadratic using the formula

- In ax² + bx + c = 0

 x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

∵ a = 1 , b = -1 , c = -1

∴ x=\frac{-(-1)+\sqrt{(-1)^{2}-4(1)(-1)}}{2(1)}=\frac{1+\sqrt{5}}{2}=1.6feet

-The value of the width is 1.6 feet

∴ The length = 1.6 × 2 = 3.2 feet

∴ The length of the diagonal = 2 + 1.6 = 3.6 feet

8 0
4 years ago
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