Question

1/3(9x+27)-4=1/2(2x+54)

Answer 1

$\frac{1}{3}(9x+27)-4= \frac{1}{2}(2x+54) \\\\\frac{1}{3} \cdot 9x+\frac{1}{3} \cdot 27 -4= \frac{1}{2} \cdot 2x+\frac{1}{2} \cdot54 \\\\=3x+9-4=x+27\\ \\3x+5=x+27\ \ |\ subtract\ x \ and \ 5\ to\ both\ \\\\3x-x+5-5=x-x+27-5\\\\2x=22 \ \ | \ divide \ both \ sides\ by\ 2 \\\\x=11$

Answer 2

First you need to distribute to everything in the parentheses.
3x+9-4=1x+27
Combine like terms
3x+5=x+27
isolate variable
3x+5=x+27
-x        -x
2x+5=27 
Whatever you do to one side do to the other so I subtract x from both sides. then you must subtract 5 from both sides

2x+5=27
-5     -5
2x=22
divide by 2
2x=22
/2   /2
x=11
Hope that helped