#1 is true. The term they have in common is y with an invisible coefficient in-front of the second y term
#2 has zero like terms. 15 has no variable, and the other terms have different variables.
#3 has two like terms, that’s 9 and 8 which add to equal 17. The answer is 3x + 17 aka D.
#4 has two like terms, the numbers with the variable ‘n’. 4n + 7n = 11n. Your answer is 11n + 12 aka D
Answer:
x = 2
Step-by-step explanation:
Taking antilogs, you have ...
2³ × 8 = (4x)²
64 = 16x²
x = √(64/16) = √4
x = 2 . . . . . . . . (the negative square root is not a solution)
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You can also work more directly with the logs, if you like.
3·ln(2) +ln(2³) = 2ln(2²x) . . . . . . . . . . . write 4 and 8 as powers of 2
3·ln(2) +3·ln(2) = 2(2·ln(2) +ln(x)) . . . . use rules of logs to move exponents
6·ln(2) = 4·ln(2) +2·ln(x) . . . . . . . . . . . . simplify
2·ln(2) = 2·ln(x) . . . . . . . . . . . subtract 4ln(2)
ln(2) = ln(x) . . . . . . . . . . . . . . divide by 2
2 = x . . . . . . . . . . . . . . . . . . . take the antilogs
The answer is -7.4166666 or written as -7.4167
Answer:
(x+7y) Squared
Step-by-step explanation:
It appears you are looking for x.
1.4+2/5x=3/15x-.08
you have to isolate the x
first add .08 to both sides
1.48+2/5=3/15x
i would now find the equivalence fraction of 2/5 with the denominator of 15. To do this you have to multiply 5 by 3 to get 15 so, you multiply the original numerator to get the equivalent one. 2(3)=6
1.48+6/15x=3/15x
now i am going to subtract 6/15x from both sides
1.48= -3/15x
to get rid of the fraction i am going to convert it to a decimal.
-3/15= -.2
1.48= -.2x
now i have to divide both sides by -.2
7.4=x
