Question

Someone help please

Answer 1

Steps to finding the line in the diagram with the format 'ax + by = c

1. Find the slope

• To find the slope, we need any two points on the line --> (0,4) and (3,0)

                  $Slope = \frac{y2-y1}{x2-x1} =\frac{4-0}{0-3} =-\frac{4}{3}$

2. Set up, with any one point on the line and the slope, in point-slope form

   

        $(y-y0)=m(x-x0)\\(y-4)=-\frac{4}{3} (x-0)\\y-4 = -\frac{4}{3} x\\\frac{4}{3}x+y = 4$

Answer: $\frac{4}{3}x+y = 4$

Hope that helps!

Answer 2

Answer:

$\sf 4x+3y=12$

Step-by-step explanation:

Choose two points on the line:

Let $\sf (x_1,y_1)=(0,4)$

Let $\sf (x_2,y_2)=(3,0)$

Use the slope formula to find the slope of the line:

$\sf slope(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0-4}{3-0}=-\dfrac43$

Use the point-slope formula to find the equation of the line:

$\sf y-y_1=m(x-x_1)$

Substitute values into the formula:

$\sf y-4=-\dfrac43(x-0)$

Expand the brackets:

$\sf y-4=-\dfrac43x$

Add 4 to both sides:

$\sf y=-\dfrac43x+4$

Rearrange into the form $ax+by=c$

Multiply both sides by 3

$\sf 3y=-4x+12$

Add 4x to both sides:

$\sf 4x+3y=12$