Answer:
x=36 1/6 or x= 36 1 over 6
Step-by-step explanation:
Answer:
- Library 2 charges more for each book loaned.
- Library 1 has a cheaper subscription fee.
Step-by-step explanation:
Based on the table, we can write the equation for the cost of borrowing from Library 2 using the two-point form of the equation of a line:
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
for (x1, y1) = (2, 15.50) and (x2, y2) = (8, 26) this equation becomes ...
y = (26 -15.50)/(8 -2)(x -2) +15.50 . . . . . fill in the values
y = (10.50/6)(x -2) +15.50 . . . . . . . . . . . . simplify a bit
y = 1.75x -3.50 +15.50 . . . . . . simplify more
In the above, we have x = number of books; y = cost. We can use "n" and "C" for those, respectively, as in the equation for Library 1. Then the monthly cost for Library 2 is ...
C = 12 + 1.75n . . . . . . . arranged to the same form as for Library 1
_____
Now, we can answer the questions.
Library 2 charges more for each book loaned. (1.75 vs 1.50 for Library 1)
Library 1 has a cheaper subscription fee. (10 vs 12 for Library 2)
_____
The numbers in the cost equations are ...
C = (subscription fee) + (cost per book loaned)·n
Answer:
a. The given equation is d = -75·t + 275 is a function
b. f(t) = -75·t + 275
c. 275 km
d. The situation does not makes sense for t > 11/2 hours.
Step-by-step explanation:
a. Given that a relation is a functional relation if for each input of a member in the relation, there is only one output for the other member, therefore;
The given equation is d = -75·t + 275 is a function
As when t = 1, d = 200 km
b. The equation written in functional notation, f(t) is f(t) = -75·t + 275
c. At the start of the journey, t = 0
Therefore;
f(0) = -75×0 + 275 = 275 km
d. The values of t that do no make sense in the function are given as follows
0 = -75×t + 275
t = 275/75 = 11/3 = 3.67 hours
For times above 3.67, the distance becomes negative
Therefore, the situation does not makes sense for t > 11/2 hours.
Answer:
G. ![\frac{11}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B20%7D)
Step-by-step explanation: