The height of the object at the time of launch is 100 meters.
To find this, we simply have to put 0 in for x, as this is when there has been no time (at launch)
h(x)=-5(x-4)^2+180
h(0)=-5(0-4)^2+180
h(0)=-5(-4)^2+180
h(0)=-5(16)+180
h(0)=-80+180
h(0) = 100
Q: "Simplify the following expression (2x+y-z)^2-(2x+y+z)^2"
As a simplified expression is
A: -8xz - 4yz
Hopefully this helps you ^0^
Answer:
j=4
Step-by-step explanation:
Divide both sides by the numeric factor on the left side, then solve.
Answer:the volume is 4x6x7.5 or 180cm^3