Question

An object is launched from a platform. It's height (in meters), x seconds after the launch, is modeled by: h(x)=-5(x-4)^2+180. What is the height of the object at the time if launch?
______meters

Answer 1

The height of the object at the time of launch is 100 meters.

To find this, we simply have to put 0 in for x, as this is when there has been no time (at launch)

h(x)=-5(x-4)^2+180

h(0)=-5(0-4)^2+180

h(0)=-5(-4)^2+180

h(0)=-5(16)+180

h(0)=-80+180

h(0) = 100