Answer:
The volume of the sawdust pile is 16041.7 feet.
Step-by-step explanation:
The sawdust pile formed is in the form of a cone.
The volume of a cone is:
The information provided is:
<em>r</em> = radius of the base = diameter ÷ 2 = (35 ÷ 2) feet
<em>h</em> = height = 50 feet
Compute the volume of the sawdust pile as follows:
Thus, the volume of the sawdust pile is 16041.7 feet.
Answer:
k = log9 / log 0.66
k = 5.3
Step-by-step explanation:
Please always remember that, when an exponential equation is given with different bases, the best approach is to take log of both sides.
If you have a calculator handy, that would be pretty fast and easy.
0.66 ^ k = 9
Take log of both sides:
klog 0.66 = log 9
k = log 9 / log 0.66
k = 0.954 / - 0.18
k = -5.3
Maths is fun, let's keep learning
Answer:
No
Step-by-step explanation:
y = -2x + 5
4 = -2(-3) + 5 - Substitute both x and y
4 = 6 + 5 - Simplify
4 ≠ 11
Hence, no, (-3, 4) doesn't statify the equation y = -2x + 5
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer:
8 lakhs = 8,00,000
Step-by-step explanation:
770000
=> 7,70,000
=> 7.7 lakhs
7.7 lakh rounded to the nearest lakh = 8 lakhs and it is Rounded Up
Hope it helps :)
