3 years ago

Find the x-and y-intercept of the equation 5x+3y=15

Mathematics

2 answers:

Sholpan [36]3 years ago

8 0

Jsjdjsjsjsjsjsjsjsjjsjsjsj I want points

Lorico [155]3 years ago

5 0

For the x intercept, let y=0
5x + 3(0)=15
5x + 0=15
5x = 15
Divide both sides by 5
X=3
(3,0)

For the y intercept, let x=0
5(0) + 3y=15
0+3y=15
3y=15
Divide both sides by 3
Y=5
(0,5)

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Read 2 more answers

Circle A’s circumference is 3 times the value of Circle B’s Area. Find Circle B’a radius.

Natali [406]

(side note: your formula C = 2πr^2 is incorrect, it should be C = 2πr)

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r = 9

Step-by-step explanation:

First let's find the circumference of Circle A. To use the formula we need radius. Since we have a diameter just divide by 2 to get radius. 27 / 2 = 13.5

Now plug that into C = 2πr: 2π*(13.5) = 27π

The question says that the area of circle B is 3x this value, so Circle B's area must be: 27π * 3 = 81π

Now plug that into A = πr^2 and solve for r:

$81\pi=\pi r^{2}\\81=r^{2}\\\sqrt{81}=r\\9=r$

(edited to correct a brain fart)

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