Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.
Answer: 0.4 miles
Step-by-step explanation:
You can use the equation y=1/5x to help you figure it out where x is the days and y is the length. y=1/5(2). y=2/5 or 0.4 miles. Please vote my answer as brainliest
The answer is 345 :) hope this helps u
Your coach can select it 4 times I think
Answer:
I am not so clear about this question