Question

I Need help. Thanks.

Answer 1

Answer:

$y\ge \:-2$

Step-by-step explanation:

$-2(5y-5)-3y \leq -7y+22$

Expand the brackets

$-10y+10-3y \leq -7y+22$

$-10y-3y+10 \leq -7y+22$

$-13y+10 \leq -7y+22$

Add 7y and -10 on both sides.

$-13y+7y \leq 22-10$

$-6y \leq 12$

Divide -6 on both sides.

$\frac{-6y}{-6}\ge \frac{12}{-6}$

$y\ge \:-2$

Answer 2

Answer:

A

Step-by-step explanation:

$-2(5y-5)-3y\leq -7y+22$

Expand parentheses:

$-10y+10-3y\leq -7y+22$

Move all y's to one side and numbers to the other:

$-6y\leq 12$

Divide both sides by -6. Since you are dividing both sides by a negative number, you need to flip the comparator:

$y\geq -2$

Hope this helps!