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kari74 [83]
3 years ago
14

How do I find the missing length of tthis triangle rounded to the nearest tenth

Mathematics
1 answer:
natta225 [31]3 years ago
6 0

What is the length of the perimeter or what is the whole area

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Kevin is making a banner with area of 7 square ft width and length of banner is whole numbers what numbers are possible dimensio
stepladder [879]

Answer:

Length = 7, width = 1.

Step-by-step explanation:

7 and 1 are the only possible dimensions as 7 is a prime number.

3 0
4 years ago
Please answer my question now in two minutes
Tresset [83]

Answer:

given,triangle EFG is congruent to triangle HIJ,THEIR corresponding sides are equal,

so, 10x=x+45

10x_x=45

or,9x=45

therefore , x=5

again,

3y = y+14

or, 3y_y=14

or, y=14/2

therefore the value of y is 7.

so the value of x is 5 and y is 7.

hope its helpful to uh...

3 0
3 years ago
Which of the following best describes the slope of the line below? A. Zero B. Negative C. Undefined D. Positive
lyudmila [28]

Answer:

C. Undefined

Step-by-step explanation:

Any vertical line is going to have an undefined slope. Plug in any two points from that line, and the formula will give you an undefined number.

Hope this helps!

4 0
3 years ago
In ∆MNP, m∠N = 90º, NH – altitude, m∠P = 21º, PM = 4 cm. Find MH.
Sveta_85 [38]

Answer:

0.51 cm

Step-by-step explanation:

In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°

By the sine definition,

\sin \angle P=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{MN}{MP}\\ \\MN=MP\sin \angle P\\ \\MN=4\sin 21^{\circ}\approx 1.43\ cm

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

\cos \angle M=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{MH}{MN}\\ \\MH=MN\cos \angle M

In the right triangle, two acute angles are always complementary, so

m\angle M=90^{\circ}-m\angle P=90^{\circ}-21^{\circ}=69^{\circ}

Thus,

MH=1.43\cos 69^{\circ}\approx 0.51\ cm

7 0
3 years ago
5.
GarryVolchara [31]
The\ volume\ of\ cylinder:V=\pi r^2 h\\\\r-radius;\ h-height\\---------------------------\\\\r=4cm;\ h=4cm\\\\therefore\\\\\boxed{V=\pi\cdot4^2\cdot4=64\pi\ (cm^3)}\leftarrow answer
5 0
3 years ago
Read 2 more answers
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