All categories

3 years ago

3/8=a/2= 15/bfind a and b

Mathematics

2 answers:

Studentka2010 [4]3 years ago

7 0

Answer:

Step-by-step explanation

$\frac{3}{8}=\frac{a}{2}\\\\\frac{3}{8}*2=a\\\\a=\frac{3}{4}\\\\\\\frac{3}{8}=\frac{15}{b}\\\\ 3*b=15*8\\\\b=\frac{15*8}{3}\\\\b=5*8\\\\b=40$

shutvik [7]3 years ago

5 0

Answer:a=3/4 and b=40

Step-by-step explanation:

To find 3/8=a/2=15/b

Firstly find a

3/8=a/2

Cross multiply

8a=3×2

8a=6

a=6/8

a=3/4

To find b

a/2=15/b

Where a=3/4

3/4/2=15/b

3/8=15/b

Cross multiply

3b=120

b=40

a=3/4 and b=40

You might be interested in

what are the values of a, b, and c in the quadratic equation –2x2 4x – 3 = 0? a a = 2, b = 4, c = 3 b a = 2, b = 4, c = –3 c a =

katrin2010 [14]

-2x² + 4x - 3 = 0

then A = -2

B = 4

C = -3

5 0

3 years ago

Read 2 more answers

If RX=4 and XS=9, then XT=<br> And how do you get it?

konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

$RS^2=RT^2+TS^2$

we have

$RS=RX+XS=4+9=13\ units$ ---> by segment addition postulate

substitute

$RT^2+TS^2=169$ ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

$RT^2=RX^2+XT^2$

we have

$RX=4\ units$

substitute

$RT^2=4^2+XT^2$

$RT^2=16+XT^2$

$XT^2=RT^2-16$ ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

$TS^2=XS^2+XT^2$

we have

$XS=9\ units$

substitute

$TS^2=9^2+XT^2$

$TS^2=81+XT^2$

$XT^2=TS^2-81$ ----> equation C

step 4

equate equation B and equation C

$TS^2-81=RT^2-16$

$TS^2-RT^2=81-16$

$TS^2-RT^2=65$ ----> equation D

step 5

Solve the system

$RT^2+TS^2=169$ ----> equation A

$TS^2-RT^2=65$ ----> equation D

Solve by elimination

Adds equation A and equation D

$RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117$

Find the value of RT^2

$RT^2+117=169\\RT^2=52$

step 6

Find the value of XT

equation C

$XT^2=117-81\\XT^2=36\\XT=6\ units$

7 0

3 years ago

Please help!

dem82 [27]

So, in this problem you already have the equations set up for how much money each one works. You have Jim, earning a starting amount of $35, plus an additional $3 for every hour he works. You also have John, who gets $8.

The variable in the equations is h, which stands for hours. From there, you can put the three different h values (6, 7, and 8) into the equations to see who gets more money.

For instance, for Day 1, Jim gets 35+3x6 dollars, or 35+18=$53, while John gets 8x6 dollars, or $48. You can substitute in 7 and 8 and do the same process to get the answers for Day 1 and 2.

Hope this helps!

7 0

3 years ago

What are the x- and y- coordinates of point P on the directed line segment from A to B such that P is Two-thirds the length of t

Maslowich

Answer: (4,-3) B

Step-by-step explanation:

7 0

3 years ago

Look at the photo and answer it pls

aleksklad [387]

Answer:

There isn't a photo

Step-by-step explanation:

There is no photo

8 0

2 years ago

3/8=a/2= 15/bfind a and b​

3/8=a/2= 15/bfind a and b