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4 years ago

How would you solve the following geometry problem?:

Mathematics

1 answer:

Fofino [41]4 years ago

5 0

What you did is correct. However the one you get is the tangent value of x. you have to find out the tan inverse of that value to find out the actual degree.

tan(x) = 33.8 / 57.6
tan(x) = 0.587
x = tan^-1 (0.587)
x = 30.4 degrees

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Select the correct answer from each drop-down menu.

ElenaW [278]

Answer:

· This image may result from the construction of an angle congruent to a given angle.

· The next step in this construction is to set the compass width to arc JK and draw an arc centered at L intersecting the existing arc through L.

Step-by-step explanation:

If the step shown above results in point of intersection P, and the construction is completed by drawing ray DP, then this construction produces triangle DLP congruent to triangle BKJ. The angle at D will be congruent to the angle at B because CPCTC. Hence an angle congruent to a given angle will have been constructed.

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3 years ago

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Please help with this

olya-2409 [2.1K]

Theyre similar so answer is B

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4 years ago

Lashonda exercises at least 50 minutes per day. Use t to represent Lashonda's amount of exercise (in minutes per day).

irinina [24]

The question is an illustration of inequalities.

The inequality that represents Lashonda's amount of exercise is: $\mathbf{t \ge 50}$

The given parameter is:

$\mathbf{Minutes = At\ least\ 50}$

In inequality, at least means greater than or equal to.

So, the above equation becomes:

$\mathbf{Minutes \ge 50}$

From the question, we understand that the number of minutes should be represented with t.

So, we have:

$\mathbf{t \ge 50}$

Hence, the inequality is: $\mathbf{t \ge 50}$

Read more about inequalities at:

brainly.com/question/15137133

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3 years ago

To find the height of a pole, a surveyor moves 160 feet away from the base of the pole and then, with a transit 6 feet tall, mea

Artyom0805 [142]

Answer:

306.8 feet

Step-by-step explanation:

Refer the attached figure .

A surveyor moves 160 feet away from the base of the pole i.e. ED = 160 m

Referring the image .

AC=ED=160 m

A transit i.e. AE is 6 feet tall.

AE = CD=6 feet

With a transmit the angle of elevation to the top of the pole to be 62° i.e. ∠BAC = 62°

To Find BC , use tigonometric ratio.

$Tan\theta = \frac{Perpendicular}{Base}$

$Tan 62^{\circ}=\frac{BC}{AC}$

$Tan 62^{\circ}=\frac{BC}{160}$

$1.88*160=BC$

$300.8=BC$

Now, the height of the pole = BC+CD =300.8+6=306.8 feet

Hence the height of the pole is 306.8 feet

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3 years ago

I bet no one can solve this....

WINSTONCH [101]

the answer is 120, i got this by finding 2/3 of 36 which is 24. i then multiplied 24 by 2, then multiplied 36 by 2, which gave me 48 and 72, and then i just added them together to get 120, hopefully this helps

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3 years ago

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