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gogolik [260]
3 years ago
5

How would you solve the following geometry problem?:

Mathematics
1 answer:
Fofino [41]3 years ago
5 0
What you did is correct. However the one you get is the tangent value of x. you have to find out the tan inverse of that value to find out the actual degree.

tan(x) = 33.8 / 57.6
tan(x) = 0.587
x = tan^-1 (0.587)
x = 30.4 degrees

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<h3><u>QUES</u><u>TION</u><u>:</u><u> </u></h3>

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<h3><u>ANSWER</u><u> </u><u>AND</u><u> </u><u>SOLU</u><u>TION</u><u>:</u><u> </u></h3>

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<u>Reduce</u><u> </u><u>first</u><u> </u><u>the</u><u> </u><u>fraction</u><u> </u><u>with</u><u> </u><u>9</u>

\large \sf  = \dfrac{x}{9}  =  \dfrac{ \cancel9}{ \cancel{27}}

<u>\large \sf =  \dfrac{x}{9}  =  \dfrac{1}{3}</u>

<u>Now</u><u> </u><u>simpli</u><u>fy</u><u> </u><u>using</u><u> </u><u>cross-multiply</u>

<u>\large \sf  = \dfrac{3x}{9}  = 1</u>

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<u>\large \sf = 3x = 9</u>

<u>Lastly</u><u> </u><u>divide</u><u> </u><u>both</u><u> </u><u>sides</u>

<u>\large \sf = 3x \div 3 = 9 \div 3</u>

<u>\large \sf = x = 9  \div 3</u>

<u>\large \sf = x = 3</u>

<h3><u>FINAL</u><u> </u><u>ANSWER</u><u>:</u></h3>

\huge \orange{ \underline{ \boxed{ \sf{x = 3}}}}

HOPE THIS HELP YOU! HAVE A NICE DAY!

~kimtaetae92~

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Answer:

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Step-by-step explanation:

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