The area of a trapezoid can be found with this formula:
Where b1 and b2 are the bases and h is the height.
If we plug in what we know we can solve for the height.
We know that b1 = 52, b2 = 42, and A = 1833. Let's solve.
No , there’s no relation because the outputs repeated the same number (3)
Answer:
12.3
Step-by-step explanation:
Step 1
We find the mean
The data list shows the scores of ten students in Mr. Smith's math class. 61, 67, 81, 83, 87, 88, 89, 90, 98, 100
Mean = Sum of terms/Number of terms
Number of terms = 10
Mean = 61 + 67 + 81 + 83 + 87 + 88 + 89 + 90 + 98 + 100/10
Mean = 844/10
Mean = 84.4
Step 2
Standard deviation
The formula for sample standard deviation =
√(x - Mean)²/n - 1
= √[(61 - 84.4)² + (67 - 84.4)² + (81 - 84.4)² + (83 - 84.4)² + (87 - 84.4)² + (88 - 84.4)² + (89 - 84.4)² + (90 - 84.4)² + (98 - 84.4)² + (100 - 84.4)²]/10 - 1
=√ 547.56 + 302.76 + 11.56 + 1.96 + 6.76 + 12.96 + 21.16 + 31.36 + 184.96 + 243.36/10 - 1
= √1364.4/9
= √151.6
= 12.31259518
Approximately to the nearest tenth = 12.3
The standard deviation = 12.3
let's first off convert the 0.6 to a fraction, and then let's keep in mind that
Standard Form of a Linear Equation
- variables must be on the left-hand-side, usually sorted in ascending order
- there must not be any fractions, just integers
- the variable "x" must not have a negative coefficient.
![\bf 0.\underline{6}\implies \cfrac{06}{1\underline{0}}\implies \cfrac{3}{5}\impliedby m = slope ~\hspace{12em} (\stackrel{x_1}{1}~,~\stackrel{y_1}{24}) \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-24=\cfrac{3}{5}(x-1)\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{5}}{5y-120=3(x-1)} \\\\\\ 5y-120=3x-3\implies -3x+5y=117\implies \stackrel{\textit{standard form}}{3x-5y=-117}](https://tex.z-dn.net/?f=%5Cbf%200.%5Cunderline%7B6%7D%5Cimplies%20%5Ccfrac%7B06%7D%7B1%5Cunderline%7B0%7D%7D%5Cimplies%20%5Ccfrac%7B3%7D%7B5%7D%5Cimpliedby%20m%20%3D%20slope%0A~%5Chspace%7B12em%7D%0A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B24%7D%29%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%0A%5Ccline%7B1-1%7D%0A%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%0A%5Ccline%7B1-1%7D%0A%5C%5C%0Ay-y_1%3Dm%28x-x_1%29%0A%5C%5C%5C%5C%0A%5Ccline%7B1-1%7D%0A%5Cend%7Barray%7D%5Cimplies%20y-24%3D%5Ccfrac%7B3%7D%7B5%7D%28x-1%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B5%7D%7D%7B5y-120%3D3%28x-1%29%7D%0A%5C%5C%5C%5C%5C%5C%0A5y-120%3D3x-3%5Cimplies%20-3x%2B5y%3D117%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bstandard%20form%7D%7D%7B3x-5y%3D-117%7D)
Answer:
A
Step-by-step explanation:
If I text him now, then I will catch him before he gets home.
If I catch him before he gets home, then he will meet me in
time.
If a then b, If b then c
Combine both conditional statements by cancelling out the middle man, which is "I will catch him before he gets home."
So you get, "If i text him now, he will meet me in time"
