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Ann [662]
3 years ago
9

How many kittens weigh at least 3/8 of a pound? (line plot)

Mathematics
2 answers:
Wittaler [7]3 years ago
6 0

Answer:

Step-by-step explanation:

d1i1m1o1n [39]3 years ago
3 0
The question is how many kittens weigh AT LEAST 3/8 of a pound. When you say at least, it means <em>greater than or equal to</em><u />. So, 

There are 4 kittens weighing 3/8 
3 kittens weighing 1/2
and 2 kittens weighing 5/8

Therefore, the answer is (4+3+2) = 9 kittens 
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Alex drew a shape that belongs to both the category of rhombuses and the category of rectangles. Alex said the most specific nam
Nina [5.8K]

Answer:

yes because a rhombus and a rectangle are counted as a quadrilateral because they have 4 sides

Step-by-step explanation:

8 0
3 years ago
How do you solve this problem? 7/10 x 1 1/3
12345 [234]

Answer:

77/30

Step-by-step explanation:

7/10 x 11/3 = 7x11 = 77 and 10x3 = 30

the answer is 77/30

5 0
4 years ago
Read 2 more answers
The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si
OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!

a) The probability that exactly 3 arrivals occur during a particular hour is:

P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\

b) The probability that <em>at least</em> 3 people arrive during a particular hour is:

P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938

c) In this case, t=0.25, so we recalculate the parameter as:

\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

E(x)=\lambda=1.5

3 0
3 years ago
a rain gauge collected 0.2 inches or rain in 30 mintues.if it keeps raining at the same rate what the total time it will take to
sveticcg [70]

Answer:

Your answer would be 2 hours and 30 minutes.

Step-by-step explanation:


8 0
3 years ago
Which strategies can be used to find the product of 629 x 100? Check all that apply.
dolphi86 [110]

Answer:

The strategies (2), (3) and (5) can be applied.

Step-by-step explanation:

In this case we need to compute the product of 629 × 100.

The product can be found in the following ways:

  • multiplying (600 + 20 + 9) x 100

       (600 + 20 + 9) \times 100=(600\times 100)+(20\times 100)+(9\times 100)\\=60000+2000+900\\=62900

  • putting 2 zeros on the end of 629

        629\times 100=62900

  • multiplying (6,000 + 200 +90) x 10

       (6000 + 200 + 90) \times 10=(6000\times 10)+(200\times 10)+(90\times 10)\\=60000+2000+900\\=62900

Thus, the strategies (2), (3) and (5) can be applied.

5 0
3 years ago
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