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Vlad [161]
3 years ago
10

Please help with this

Mathematics
2 answers:
alina1380 [7]3 years ago
7 0

Answer:

d the last one

Step-by-step explanation:

18/3 mark me as brainlist plz

Jlenok [28]3 years ago
3 0

Answer:

18/3

Step-by-step explanation:

only multiply the numerator

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carlos hiked 1 3/4 miles along a nature trail to a fork in the trail. he then hiked 2 1/2 miles along a path that led to a water
Lelechka [254]

Answer:

3/4 miles longer

Step-by-step explanation:

its 1 3/4 the other is only 1. so answer is 3/4

4 0
3 years ago
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MaRussiya [10]

Answer:

B

Step-by-step explanation:

Yes, it is. The set of rational numbers is closed for all the four operations, so x+y, x-y, x*y and x/y are rational too. And it is easy to demonstrate. A rational number can be expressed as a fraction of two integers. So, x can be expressed as a/b and y as c/d. Hence x+y = a/b + c/d = (ad+bc)/bd, which, as fraction of two integers, is rational.

8 0
3 years ago
Help! pls this is urgent don't mind me
Stels [109]

Answer:

hey.

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
NEED HELP WILL MARK BRANLYEST
BlackZzzverrR [31]

Answer:

The first of the rows should go with each other. The 36/125^3 does with the second one. The 6/125^3 goes to the third one. The last row goes with 8/125 cm^3

Step-by-step explanation:

6 0
3 years ago
Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:
ryzh [129]

First find the critical points of <em>f</em> :

f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7

\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1

\dfrac{\partial f}{\partial y}=6y=0\implies y=0

so the point (1, 0) is the only critical point, at which we have

f(1,0)=-7

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t

Find the critical points of <em>g</em> :

\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0

\implies\sin t=0\text{ OR }1+5\cos t=0

\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi

where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at

t=0\implies f(10,0)=155

t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299

t=\pi\implies f(-10,0)=235

t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299

So <em>f</em> has a minimum of -7 and a maximum of 299.

4 0
3 years ago
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