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Paul [167]
4 years ago
14

How to figure compound interest

Mathematics
1 answer:
zaharov [31]4 years ago
5 0
Compound interest formula (annual)
A = P(1 + i)^n 
where A = total/final amount
P = principal/initial/beginning amount
i = interest rate 
n = number of years

OR if interest was calculated in different time periods such as monthly, semiannually, fortnightly, weekly, daily etc 
A = P(1 + i/k)^n
where k = number of periods in that year
n = kt = number of periods * number of years 
e.g. if interest was calculated monthly for 2 years
k would be 12 & n would be 12*2 = 24
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aleksandr82 [10.1K]
C = 48
c = 2a - 4

48 = 2a - 4
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4 0
3 years ago
Cual es la razon de 0.240 y 0.12
Kamila [148]

Answer:

8686787876876

Step-by-step explanation:

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3 years ago
Find to the nearest square foot the total surface area of a cylinder with radius 7ft and height 9 ft.
Ilia_Sergeevich [38]

Answer:

d is the answer

Step-by-step explanation:

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7 0
3 years ago
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Whats the answer 3(x – 4) ≥ 5x + 2
Mumz [18]

Answer:

x≤−7

Step-by-step explanation:

Let's solve your inequality step-by-step.

3(x−4)≥5x+2

Step 1: Simplify both sides of the inequality.

3x−12≥5x+2

Step 2: Subtract 5x from both sides.

3x−12−5x≥5x+2−5x

−2x−12≥2

Step 3: Add 12 to both sides.

−2x−12+12≥2+12

−2x≥14

Step 4: Divide both sides by -2.

−2x

−2

≥

14

−2

x≤−7

Answer:

x≤−7

5 0
3 years ago
Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
Mice21 [21]

Answer:

KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM  

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

So,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

and

\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

3 0
3 years ago
Read 2 more answers
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