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Tems11 [23]
3 years ago
6

the angle of elevation of the top of a tower from a point 42m away from the base on level ground is 36 find the height of the to

wer​
Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

30.51 meters

Step-by-step explanation:

Given that:

The distance from the point to the base of the tower = 42 m, the angle of elevation = 36°.

According to sine rule if a,b,c are the sides of a triangle and its respective opposite angles are A, B, C. Therefore:

\frac{a}{sin(A)} =\frac{b}{sin(B)}=\frac{c}{sin(C)}

Let the height of the tower be a and the angle opposite the height be A = angle of elevation = 36°

Also let the  distance from the point to the base of the tower be b = 42 m, and the angle opposite the base of the tower be B

To find B, since the angle between the height of the tower and the base is 90°, we use:

B + 36° + 90° = 180° (sum of angles in a triangle)

B + 126 = 180

B = 180 - 126

B = 54°

Therefore using sine rule:

\frac{a}{sin(A)} =\frac{b}{sin(B)}\\\\\frac{a}{sin(36)}=\frac{42}{sin(54)}\\\\  a=\frac{42*sin(36)}{sin(54)}\\ \\a=30.51\ meters

The height of the tower is 30.51 meters

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