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Alex_Xolod [135]
3 years ago
14

Yusef drove 130 miles in 2.5 hours. Which equation can be used to calculate r, the average speed at which Yusef drove?

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
6 0
130/2.5 is 52
You are very welcome
sergejj [24]3 years ago
4 0
130m = 2.5h (h= hours)
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A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime
MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let \mu = <u><em>true average percentage of organic matter</em></u>

So, Null Hypothesis, H_0 : \mu = 3%      {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, H_A : \mu \neq 3%      {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean percentage of organic matter = 2.481%

             s = sample standard deviation = 1.616%

            n = sample of soil specimens = 30

So, <u><em>the test statistics</em></u> =  \frac{2.481-3}{\frac{1.616}{\sqrt{30} } }  ~ t_2_9

                                     =  -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have <u><em>sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have <u><em>insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

8 0
3 years ago
PLEASE HELP
BARSIC [14]
Just do 23 minus 6 and that should be the answer because the y-ccordinate is in the same place

3 0
3 years ago
Sofia jarred 18 liters of jam after 6 days. How many days does Sofia need to spend making jam if she wants to jar 30 liters of j
Novay_Z [31]

Answer:

10 Days

Step-by-step explanation:

First u need to find out how many liters of jam she made every day so you have to do 18 divided by 6 = 3, she made 3 jams each day. The question is asking how much days she needs to make 30 liters of Jam so divided 30 by 3 and u will get your answer which is 10

6 0
3 years ago
Find the surface area of the figure.
Darina [25.2K]
B, 224in2

It may get tedious but just find the area of each face and write them down
4 0
3 years ago
Can someone help me on this with the steps? thanks!
soldi70 [24.7K]

Answer:

8h + 15 = 39

Step-by-step explanation:

The base fee is 15 so you shouldn't multiply the hours by it.

The question states 8 per hour which means that you should multiply the 8 by hours and add on the base fee which is 15.

8 0
3 years ago
Read 2 more answers
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